| Charles Hutton - Mathematics - 1811 - 494 pages
...measure the distance FA. To prove the work ; add all the inward angles A, B, c, &c, together ; for when the work is right, their sum will be equal to...many right angles as the figure has sides, wanting 4 right angles. But when there is an angle, as f, that bends inwards, and you measure the external... | |
| Charles Hutton - Mathematics - 1811 - 406 pages
...triangles, is equal to two right angles (th. 17); therefore the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point P, which are so many many of the angles of the triangles,... | |
| Charles Hutton - Mathematics - 1812 - 620 pages
...intvard angles, as the figure has sides : therefore the sum of all the inward and outward angles, is equal to twice as many right angles as the figure has sides. But the sum of all the inward angles, with four right angles, is equal to twice as many right angles... | |
| Euclides - 1816 - 588 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Cor. 2. All the exterior angles of any rectilineal figure' are together equal to four right angles.... | |
| John Playfair - Circle-squaring - 1819 - 350 pages
...all the angles of the figure, together with four right angles, that is, the angles of the figure are equal to twice as many right angles as the figure has sides, wanting four. COR. 2. All the exterior angles of any rectilineal figure are tegether equal to four right angles.... | |
| John Playfair - 1819 - 354 pages
...many right angles as the figure has sides, wanting four. For all the angles exterior and interior are equal to twice as many right an,gles as the figure has sides ; but the exterior are equal to four right angles ; therefore the interior are equal to twice as many... | |
| Euclid - 1822 - 222 pages
...Cor. 6. All the internal angles of any rectilineal figure, ABCDE, together with four right angles, are equal to twice as many right angles as the figure has sides. Take any point F within the figure and draw the right lines FA, FB, FC, FD, and FE. There are formed... | |
| Rev. John Allen - Astronomy - 1822 - 516 pages
...FC, FD, FE ; there are formed as many triangles as the figure has sides, all the angles of which are equal to twice as many right angles as the figure has sides [by this prop.] ; but of these all the angles about the point F are equal to four right angles [Ctor.... | |
| Charles Hutton - Mathematics - 1822 - 616 pages
...triangles, is equal to two right angles (th. 17) ; therefore the sum of the angles of all the triangles is equal to twice as many right angles as the figure has sides. But the sum of all the angles about the point p, which are so / many of the angles of the triangles,... | |
| Edward Riddle - Nautical astronomy - 1824 - 572 pages
...angles as the figure has sides. But all the interior angles, and four right angles, are also together equal to twice as many right angles as the figure has sides, (Theo. 25.) Hence the interior and the exterior angles of the figure are, together, equal to the interior... | |
| |