 | Daniel Barnard Hagar - Algebra - 1873 - 278 pages
...same number of 7x 7x miles; hence, we have f(a; — 8)=— ; whence, x = 50, and — = 70. 5 5 20. A privateer, running at the rate of 10 miles an hour, discovers a ship 18 miles off, running at the rate of 8 miles an hour. How many miles can the ship run before it is overtaken ? Ans.... | |
 | Isaac Todhunter - Algebra - 1876 - 350 pages
...therefore 23* = 46; therefore x = 2. Thus the stocks at first were 10, 30, 24, 28. EXAMPLES. XXII. 1. A privateer running at the rate of 10 miles an hour discovers a ship 1 8 miles oft', running at the rate of 8 miles an hour: how many miles can the ship run before it is... | |
 | Thomas Kimber - 1880 - 176 pages
...(2) when it is at the centre of the circle. 1849. Monday, Oct. 22nd. — Examiner, — Mr. JERRARD. 1. What is the meaning of the term multiplication,...privateer running at the rate of 10 miles an hour, disIcovers a ship 18 miles off, making way at the rate of 8 miles an hour : how many miles can the... | |
 | Edward Albert Bowser - Algebra - 1888 - 868 pages
...days, which A alone could reap in 10 days : in what time could B alone reap it? Ans. 23^ days. 52. A privateer, running at the rate of 10 miles an hour, discovers a ship 18 miles off, running at the rate of 8 miles an hour : how many miles can the ship run before it is overtaken? Ans.... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 444 pages
...hours, and the other at the rate of 5 miles in 4 hours. Where will they meet ? 40. A privateer sailing at the rate of 10 miles an hour discovers a ship 18 miles off sailing at the rate of 8 miles an hour. How many miles can the ship sail before it is overtaken ? 41.... | |
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A privateer running at the rate of 10 miles an hour discovers a ship 1 8 miles off making way at the rate of 8 miles an hour : how many miles can the ship run before being overtaken? 
