 | Peter Nicholson - Cabinetwork - 1856 - 482 pages
...parallel to CD, the alternate angles, GFE, FGH, are also equal ; therefore the two triangles GEF, HFG, have two angles of the one equal to two angles of the other, each to each ; and the side FG, adjacent to the equal angles, common ; the triangles are therefore equal (theorem 6) ;... | |
 | Euclides - 1856 - 168 pages
...BAC, and the angle ABE is equal to the angle ABC (being both right angles), the triangles ABC, ABE have two angles of the one equal to two angles of the other, and the side AB common to the two. Therefore the triangles ABC, ABE are equal, and the side AE is equal... | |
 | Elias Loomis - Conic sections - 1857 - 242 pages
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG have two angles of the one equal to two angles of the other, each to each, and the side Eli included between the equal angles, common ; hence the triangles are equal (Prop. VII.)... | |
 | Adrien Marie Legendre - Geometry - 1857 - 444 pages
...consequently, the two equiangular triangles BA C, CUD, are similar figures. Cor. Two triangles which have two angles of the one equal to two angles of the other, are similar; for, the third angles are then equal, and the two triangles are equian gular (BI, p. 25,... | |
 | Euclides - 1858 - 248 pages
...to assist in the demonstration of the following propositions. PROP. 26.— THEOR. — (Important.) If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz., either the sides adjacent to the equal angles in each, or the sides... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG have two angles of the one equal to two angles of the other, each to each, and the side Eli included between the equal angles, common ; hence the triangles are equal (Prop. VII.)... | |
 | Euclides - 1868 - 88 pages
...Hyp. Cone. Sap. HP 24. HypConol. D. 5. 9. Concl. Recap. PROP. XXVI. THEOR. If tu-o triangles have t\co angles of the one equal to two angles of the other, each to and one side equal to one side, viz., either the sides adjacent to the equal angles in each, or the... | |
 | W. Davis Haskoll - Civil engineering - 1858 - 424 pages
...angle in each, contained by proportional sides, are similar to each other. Any two triangles having two angles of the one equal to two angles of the other, are similar triangles, because the three angles of the one triangle are equal to the three angles of... | |
 | New Brunswick. Board of Education, New Brunswick. Department of Education - Education - 1893 - 804 pages
...as many misses as B. Find the number of hits *• and misses of each. GEOMETRY. Time, 3 hn. 1 . (a) If two triangles have two angles of the one equal to two angles of the other each to each, and one side equal to one side, those sides being opposite equal angles in each, then must triangles be... | |
 | New Brunswick. Board of Education, New Brunswick. Department of Education - Education - 1893 - 800 pages
...many misses as B. Find the number of hits 1 00 and misses of each. GEOMETRY. Time, 2 hrs. 13 1. (a) If two triangles have two angles of the one equal to two angles of the other each to each, and one side equal to one side, those sides being opposite equal angles in each, then must triangles be... | |
| |