| Peter Nicholson - Cabinetwork - 1856 - 482 pages
...parallel to CD, the alternate angles, GFE, FGH, are also equal ; therefore the two triangles GEF, HFG, **have two angles of the one equal to two angles of the other, each to each ; and** the side FG, adjacent to the equal angles, common ; the triangles are therefore equal (theorem 6) ;... | |
| Euclides - 1856 - 168 pages
...BAC, and the angle ABE is equal to the angle ABC (being both right angles), the triangles ABC, ABE **have two angles of the one equal to two angles of the other,** and the side AB common to the two. Therefore the triangles ABC, ABE are equal, and the side AE is equal... | |
| Elias Loomis - Conic sections - 1857 - 242 pages
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG **have two angles of the one equal to two angles of the other, each to each, and** the side Eli included between the equal angles, common ; hence the triangles are equal (Prop. VII.)... | |
| Adrien Marie Legendre - Geometry - 1857 - 444 pages
...consequently, the two equiangular triangles BA C, CUD, are similar figures. Cor. Two triangles which **have two angles of the one equal to two angles of the other,** are similar; for, the third angles are then equal, and the two triangles are equian gular (BI, p. 25,... | |
| Euclides - 1858 - 248 pages
...to assist in the demonstration of the following propositions. PROP. 26.— THEOR. — (Important.) **If two triangles have two angles of the one equal to two angles of the other, each to each, and** one side equal to one side, viz., either the sides adjacent to the equal angles in each, or the sides... | |
| Elias Loomis - Conic sections - 1858 - 256 pages
...is parallel to CD, the alternate angles GHE, HEF are also equal. Therefore, the triangles HEF, EHG **have two angles of the one equal to two angles of the other, each to each, and** the side Eli included between the equal angles, common ; hence the triangles are equal (Prop. VII.)... | |
| Euclides - 1868 - 88 pages
...Hyp. Cone. Sap. HP 24. HypConol. D. 5. 9. Concl. Recap. PROP. XXVI. THEOR. If tu-o triangles have t\co **angles of the one equal to two angles of the other, each to** and one side equal to one side, viz., either the sides adjacent to the equal angles in each, or the... | |
| W. Davis Haskoll - Civil engineering - 1858 - 424 pages
...angle in each, contained by proportional sides, are similar to each other. Any two triangles having **two angles of the one equal to two angles of the other,** are similar triangles, because the three angles of the one triangle are equal to the three angles of... | |
| New Brunswick. Board of Education, New Brunswick. Department of Education - Education - 1893 - 804 pages
...as many misses as B. Find the number of hits *• and misses of each. GEOMETRY. Time, 3 hn. 1 . (a) **If two triangles have two angles of the one equal to two angles of the other each to each, and** one side equal to one side, those sides being opposite equal angles in each, then must triangles be... | |
| New Brunswick. Board of Education, New Brunswick. Department of Education - Education - 1893 - 800 pages
...many misses as B. Find the number of hits 1 00 and misses of each. GEOMETRY. Time, 2 hrs. 13 1. (a) **If two triangles have two angles of the one equal to two angles of the other each to each, and** one side equal to one side, those sides being opposite equal angles in each, then must triangles be... | |
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