 | James H. Porter - Arithmetic - 1845 - 252 pages
...Suppose 4 men in 12 days mow 48 acres, how many acres can 8 men mow in 16 days 1 Ans. 128 acres. 32. If 10 bushels of oats be sufficient for 18 horses...days, how many bushels will serve 60 horses 36 days ? Ans. 60 bushels. 33. If 4 dollars be the hire of 8 men for 3 days, how many days must 20 men work... | |
 | Arithmetic - 1845 - 210 pages
...АЛ Г 100 direct fifiD. v 7m. •< p inverse Contracted. 5 j (.12 )#h (700(20 Ans. M 420 1200 4. If 10 bushels of oats be sufficient for 18 horses...days, how many bushels will serve 60 horses 36 days, at that rate ? ' Ans. 60 bu. 5. If 7 quarters of malt are sufficient for a family of 7 persons 4 months,... | |
 | James H. Porter - Arithmetic - 1845 - 254 pages
...mow 48 acres, how many acres can 8 men mow in 16 days ? Ans. 128 acres. 32. If 10 bushels of oats he sufficient for 18 horses 20 days, how many bushels will serve 60 horses 36 days 1 Ans. 60 bushels. 33. If 4 dollars be the hire of 8 men for 3 days, how many days must 20 men work... | |
 | Almon Ticknor - Arithmetic - 1846 - 276 pages
...receive 12D. for 3 days' work, how many men will it require to earn 48D. in 16 days? Ans. 3. 1 1. If 100 bushels of oats be sufficient for 18 horses 20 days, how many bushels will 60 horses require in 36 days ? Ans. 600 bushels. 12. If the transportation of 8 cwt. cost Dl2.80 for... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...? 15. If 12 oxen in 16 days eat 20 acres of grass, how many acres will serve 24 oxen 48 days ? 16. If 10 bushels of oats be sufficient for 18 horses...days, how many bushels will serve 60 horses 36 days, at that rate ? 17. If 2 men can do 12 rods of ditching in 6 days, how many rods may be done by 8 men... | |
 | Arithmetic - 1853 - 266 pages
...0 3. Suppose 4 men in 12 days mow 48 acres, how many acres can 8 men mow in 16 days? Ans. 128A. 4. If 10 bushels of oats be sufficient for 18 horses...days, how many bushels will serve 60 horses 36 days, at that rate? Ans. 60bu. 5. Suppose the wages of six persons for 21 weeks be 288 dollars, what must... | |
 | Arithmetic - 1852 - 196 pages
...direct H$ D. >• 7 m. \ $ inverse Contracted. V ' ^ 100(20 Ans 5 ) 12 420 1200 * r 7m' 7 4. If 1 0. bushels of oats be sufficient for 18 horses 20 days, how many bushels will serve 60 horses 36 days, at that rate? Ans. 60 bu. 5. If 7 quarters of malt are sufficient for a family of 7 persons 4 months,... | |
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If 10 bushels of oats be sufficient for 18 horses 20 days, how many bushels will serve 60 horses 36 days ? Ans. 
