 | James Bates Thomson - Arithmetic - 1847 - 426 pages
...second term, and the other for the first. III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer together,... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...name mentioned. 2. Multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination as the third term. 3. If either of the terms consists of fractions, state the question as in whole... | |
 | James Bates Thomson - Arithmetic - 1848 - 434 pages
...second term, and the other for the first. III. Finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the tame denomination as the third term. PROOF. — Multiply the first term and the answer together,... | |
 | Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the first term ; the quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | John Bonnycastle - 1851 - 314 pages
...and the third to the lowest denomination mentioned in it. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ; which must be brought again, if necessary,... | |
 | Arithmetic - 1851 - 260 pages
...consist of several denominations, reduce it to the lowest, then Multiply the second and third terms together and divide the product by the FIRST, and the quotient will be the fourth term or answer. NOTE.— The answer will be of the same denomination as the third term,' and,... | |
 | Roswell Chamberlain Smith - 1852 - 298 pages
...denomination mentioned in it 3. Divide the product of the second and third terms by the first term ; the quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | David Price - Arithmetic - 1858 - 264 pages
...terme— 1st ? 2d 1 What is the rule for working— 1st ? 2d ? divide the product by the first term ; the quotient will be the answer to the question, in the same denomination to which the third term was reduced. ID" Sometimes it will be best to reduce the terms before you make... | |
 | James Bates Thomson - Arithmetic - 1860 - 440 pages
...second term, and the other for the first. III. Finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the game denomination as the third term. PROOF. — Multiply the first term and the answer together,... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...number of the supposition, the second (153, Ex. 2 and 3). IV. Multiply the third term by the second, and divide the product by the .first, and the quotient will be the fourth term, or answer sought; or, multiply the given ratio by the third term, and the product will... | |
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Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. 
