 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the first term ; the quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the jirst term ; the quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | Nathan Daboll - 1843 - 260 pages
...in it. 5. Multiply the second and third terms together, and divide their product by the first term: the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. The method of proof is by inverting... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 pages
...fractions, having the 1st and 2nd terms in the same denomination ; then multiply the 2nd and 3rd terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination as the third term is left in. EXAMPLES. 1. Bought 3cwt. 2qrs. 14 Ib. of sugar... | |
 | Alfred Crowquill - Arithmetic - 1843 - 156 pages
...then bring the first and third numbers into one name, and the second into the lowest term mentioned. Multiply the second and third numbers together, and divide the product by the first; the quotient will be the answer to the question in the same denomination you left the second number... | |
 | William Lane (of Worthing.) - 1845 - 138 pages
...contains. Then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer to the question, in the same denomination that the third term was reduced to ; which must be brought again, if necessary, to the highest denomination... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...mentioned in it. 3. — Multiply the second and third terms together and divide the product by the first, the quotient will be the answer to the question in the same name the second term was brought into. The method of proof is by inverting the question. EXAMPLES.... | |
 | James Bates Thomson - Arithmetic - 1846 - 402 pages
...second term, and the other for the first. III. Finally, multiplying the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer or fourth... | |
 | James Bates Thomson - Arithmetic - 1846 - 354 pages
...term, and t/ce other for the first. III. Finally, multiplying the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer or fourth... | |
 | James Bates Thomson - Arithmetic - 1846 - 362 pages
...second term, and the other for the first. IIL Finally, multiplying the second and third terms togethf-r, divide the product by the first, and the quotient will be the. answer in the same denomination as the third term. PROOF. — Multiply the first term ami the ansmr together,... | |
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Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. 
