 | Richard Frederick Clarke (the elder.) - 1833 - 158 pages
...name, and the third into the lowest denomination mentioned. 4th. Multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or answer, in the same denomination the third term was left in. NOTE. It is often required... | |
 | Francis Walkingame - 1835 - 270 pages
...mentioned in it, then multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination the third term was reduced to, and must be reduced to the highest denomination it admits of. Note.... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...reduce the lower denominations to the decimal of the highest. 3. Multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in that denomination which the third term was left in. In arranging the first two terms, we have only... | |
 | A. Turnbull - Arithmetic - 1836 - 368 pages
...denomination contained in it. The three terms thus reduced, we multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term in the same denomination, to which the third term has been reduced. See paragraph 240 :... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...mentioned in it. 3. Multiplythesecond and third terms together and divide their product by the first term; the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. The method of proof is by inverting... | |
 | Roswell Chamberlain Smith - 1837 - 306 pages
...denomination mentioned in it. 3. Divide the product of the second and third terms by the first term ; th« quotient will be the answer to the question, in the same denomination with the second term, which may be brought into any other denomination required. The Rule of Three... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...reduce the lower denominations to tha daeimil «f the highest 3. Multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in that denomination which the third term was bft in. In arranging the first two terms, we have only... | |
 | Thomas Holliday - Surveying - 1838 - 404 pages
...Having stated the question according to the proper rule or case, multiply the second and third terms together and divide the product by the first, and the quotient will be the fourth term required for the natural number. But in working by logarithms, the second and third terms... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...denomination mentioned. Multiply the second and third terms together, and divide the product by the first : the quotient will be the answer to the question, in the same denomination you left the third term in. Proof. — Invert the question ; that is, place the answer for the first term, the third... | |
 | Robert Goodacre - 1839 - 320 pages
...multiply all those which are not marked for a general dividend. Divide the dividend by the divisor : the quotient will be the answer to the question in the same denomination as the middle term was left in when it was multiplied with the others. Example worked. If 7 men in... | |
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Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. 
