 | John Dozell - Arithmetic - 1827 - 190 pages
...the first and third numbers into one denomination, and the second it'to the lowest term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination as you left the second number... | |
 | Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 222 pages
...and the other on the left for the first term. 3. Multiply the second and third terms together, divide by the first, and the quotient will be the answer to the question, which, 231 . What it the nature of these useless distinction! ? 232. What is the general (as also the... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination as that to which the... | |
 | William Slocomb - 1828 - 160 pages
...mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second term, and may be brought into any other denomination required. Continue... | |
 | Nathan Daboll - Arithmetic - 1828 - 262 pages
...it. 3. Multiply the second and third terms-togethicr, and divide th«ir product by the first term l the quotient, will be the answer to the question, in the same denemination you left the second term in, which may be brought into any other denomination required..... | |
 | William Kinne - 1829 - 246 pages
...'numbers in the third place, and the other in the first. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. NOTE 1. — 1t is sometimes most convenient to multiply and divide as in Compound Multiplication and... | |
 | Thomas Smith (of Liverpool.) - 1830 - 282 pages
...multiply all the terms together that are not marked, and to divide the product by those that are marked ," and the quotient will be the answer to the question, in the same denomination as that in which you left the second term." Precepts without examples, are of little avail, whether... | |
 | Michael Walsh - 1831 - 348 pages
...first and third numbers into the same, and the second into the lowest denomination mentioned in it. 2. Multiply the second and third numbers together, and...divide the product by the first, and the quotient (if there be no remainder) is the answer, or fourth number required. NOTE. In multiplying the second... | |
 | Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...Question. 1. Multiply the second and third terms together, and divide the product by the first term- The quotient will be the answer to the question in the same name or denomination the second term was left in. This you must remember; for, by it, you can determine... | |
 | Francis Walkingame - 1832 - 224 pages
...then bring the first and third numbers into one name, and the second into the lowest term mentioned. Multiply the second and third numbers together, and divide the product by the first, the quotient will be the answer to the question in the same denomination you left the second number... | |
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Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. 
