...both to the root and the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product from the dividend, and...remainder bring down the next period for a new dividend. If the product should be greater than the dividend, diminish the last figure of the root. 5. Double...

...of the three parts will be the complete divisor, which multiply by the last figure of the root, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. Proceed in same way, until all the periods are brought down. EXAMPLE. Find the cube root of 111215247129....

...right of the partial divisor; multiply the divisor thus completed by the figure last placed in the root; subtract the product from, the dividend, and to the remainder bring down t/ie next period for a new dividend. IV. Double the root already found, for a new partial divisor,...

...and also annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and...remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but one figure ; each of the others will contain two....

...the result will be the complete divisai'. V. Multiply the. complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring flown another period for a new dividend. VI. Add together the last complete divisor, the last correction,...

...and the square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and...remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue...

...at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the rootj subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods...

...the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a, new dividend. VI. Add together the last complete divisor, the last correction,...

...true divisor thus obtained by the last term of the root, and subtract this product from the dividend ; to the remainder bring down the next period for a new dividend. Double the terms of the root already found for a new trial divisor, and proceed as before. NOTE I....

...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Multiply the square of the terms of the root already found (considered as fens), by three for a trial...