 | William Kent - Engineering - 1902 - 1224 pages
...angle = 180° — sum of the two angles. 2. The sides may be found by the following proportion : • The sine of the angle opposite the given side is to the sine of the angle opposite the required side as the given s'de is to the required side. CASE II. Given two sides and an angle opposite one of them,... | |
 | Fred Lavis - Railroads - 1906 - 308 pages
...A a = c Sin A b = c Cos A. Solution of Any Plane Triangle. Case 1. — Given 2 angles and one side. Sine of the angle opposite the given side is to the sine of the angle opposite the required side as the given side is to the required side. Example. Given BC a A = 180 — (B + C) Then Sin A : Sin... | |
 | William Miller Barr - Engineering - 1918 - 650 pages
...Us opinante angle arc two of the given parts. Rule 1. To find a Me, work the following proportion: as the sine of the angle opposite the given side is...required side, so is the given side to the required side. Rule 2. Го find an angle: as the side opposite to the given angle is to the side opposite to the... | |
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As the sine of the angle opposite the given side, is to the sine of the angle opposite the required side ; so is the given side to the required side. 
