 | James Gray - Arithmetic - 1854 - 120 pages
...of these three by the figure last placed in the root, and subtract the product from the dividend. 6. To the remainder bring down the next period for a new dividend, with which proceed as before. Or add up the three last numbers, reckoning the middle ' one twice in the operation ; to this sum annex... | |
 | Charles Davies, William Guy Peck - Mathematics - 1855 - 628 pages
...Multiply the divisor thus obtained by the last digit of the root found ; subtract ïhe product from the dividend, and to the remainder bring down the next period for a new dividend. If the product just found exceeds the dividend, diminish the last digit of the root found, and proceed... | |
 | Benjamin Peirce - Algebra - 1855 - 308 pages
...divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue the operation as before, until all the periods... | |
 | George Roberts Perkins - Arithmetic - 1855 - 388 pages
...its next term. Multiply this term by the last found figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a NEW DIVIDEND. Proceed as before until all the periods have been brought down. NOTE 1. — When any dividend is not... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor, and continue... | |
 | Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...given power, and subtract it from as many left hand periods as the root has places of figures. 17. To the remainder bring down the next period for a new dividend, to which find a new divisor as before, and so on till the period* are all brought down. 18 What is... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. To the last true divisor and the number immediately over it, add the square of the last root figure,... | |
 | Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Charles Guilford Burnham - 1857 - 342 pages
...cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from tlte dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? Operation.... | |
 | Joseph Ray - Arithmetic - 1857 - 348 pages
...Multiply the complete dicisor by the last figure of the root, and subtract the product from the dividend; to the remainder bring down the next period for a new dividend, and so proceed until all the periods are brought down. NOTES. — 1. When the product of the complete... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
