 | Thomas Sherwin - 1862 - 252 pages
...figure previously found, and also at the right of the divisor. Multiply the divisor, thus increased, by the last figure of the root, and subtract the product from the whole dividend. 4. Repeat the process in part third of the rule, until all the periods have been brought... | |
 | James Bates Thomson - Arithmetic - 1862 - 428 pages
...of the partial divisor; multiply the divisor thus completed by the figure last placed in the root; subtract the product from, the dividend, and to the remainder bring down t/ie next period for a new dividend. IV. Double the root already found, for a new partial divisor,... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a, new dividend. VI. Add together the last complete divisor, the last correction,... | |
 | Charles Davies - Arithmetic - 1865 - 372 pages
...also annex it to the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
 | W H. Wingate - 1865 - 150 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take from the dividend, and to the remainder bring down the next period, and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
 | Robert Thomson (of Southampton.) - Marine engineers - 1866 - 180 pages
...the unit's place of the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next point for a new dividend, double the last figure set in the divisor and proceed as before to the last... | |
 | Thomas Percy Hudson - Arithmetic - 1866 - 268 pages
...part of the root already obtained, and also to the partial divisor. Multiply the divisor thus formed by the last figure of the root, and subtract the product from the dividend, bringing down the next period to the right of the remainder for a dividend. Continue the operation... | |
 | Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...the right of the divisor ; multiply the divisor, thus increased, by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend. 4. Multiply the quotient — the root so far found (now consisting of two figures) — by... | |
 | Joseph Ray - Arithmetic - 1857 - 358 pages
...the root, and add these two products to the trial divisor; the sum will be the COMPLETE divisor. 4. Multiply the complete divisor by the last figure of...root, and subtract the product from the dividend; to the remainder bring down the next period for a new dividend, and so proceed until all the periods... | |
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... by the last figure of the root, and subtract the product from the dividend ; to the remainder bring down the next period for a new dividend. 
