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" Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides. "
Complete School Algebra - Page 466
by Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1919 - 507 pages
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Numerical Problems in Plane Geometry with Metric and Logarithmic Tables

Joe Garner Estill - Geometry - 1896 - 168 pages
...of the other are to each other as the products of the sides including the equal angles, prove that the bisector of an angle of a triangle divides the opposite side into parts which are proportional to the sides adjacent to them. 5. Prove that the circumferences of two...
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New Plane and Spherical Trigonometry, Surveying and Navigation

George Albert Wentworth - Trigonometry - 1896 - 394 pages
...В' - tan Л ; b sin В sin A sin C ' sin В sin C — c. 2. Prove by means of the Law of Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides. Let CD bisect angle C. Then AD CD sin A But By division,...
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Elements of Geometry

Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 376 pages
...Substituting this value in (2), SUMMARY : &1 = i § 305 § 305 Q ED +ct. PROPOSITION XX. THEOREM 314. The bisector of an angle of a triangle divides the opposite side into segments which arc proportional to the other two sides. GIVEN — in the triangle ABC, AD the bisector of the angle...
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Plane and Spherical Trigonometry, Surveying and Tables

George Albert Wentworth - Logarithms - 1897 - 384 pages
...of § 33 become when one of the angles is a right angle ? 2. Prove by means of the Law of Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides. 3. What does Formula [26] become when -4 = 90° ? when .4...
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The Elements of Geometry

Henry W. Keigwin - Geometry - 1897 - 254 pages
...of the other are to each other as the products of the sides including the equal angles, prove that the bisector of an angle of a triangle divides the opposite side into parts which are proportional to the sides adjacent to them. 15. A quarter-mile running-track consists...
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Entrance Examinations in Mathematics, 1884 to 1898 [with Supplements to 1900]

Yale University - 1898 - 212 pages
...circle having its center in a given line and passing through two given points. 3. The bisector of the angle of a triangle divides the opposite side into segments which are proportional to the two other sides. 4. If two angles of a quadrilateral are bisected by oueof its diagonals, the quadrilateral...
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Yale University Entrance Examinations in Mathematics: 1884 to 1898

Mathematics - 1898 - 228 pages
...circle having its center in a given line and passing through two given points. 3. The bisector of the angle of a triangle divides the opposite side into segments which are proportional to the two other sides. 4. If two angles of a quadrilateral are bisected by one of its diagonals, the quadrilateral...
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Plane and Solid Geometry: Inductive Method

Arthur A. Dodd, B. Thomas Chace - Geometry - 1898 - 468 pages
...circle having its center in a given line and passing through two given points. 3. The bisector of the angle of a triangle divides the opposite side into segments which are proportioned to the two other sides. triangles and the two diagonals of the quadrilateral are perpendicular...
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Plane Geometry

George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...such that M'A:M * B = 3:5. (2) Comparing (1) and (2), MA: MB = M'A: M'B. PROPOSITION XV. THEOREM. 348. The bisector of an angle of a triangle divides the...segments which are proportional to the adjacent sides. E AMB Let CM bisect the angle C of the triangle CAB. To prove that MA : MB = CA : CB. Proof. Draw AE...
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Plane and Solid Geometry

William James Milne - Geometry - 1899 - 404 pages
...bisector compare with the ratio of the sides of the triangle adjacent to these segments ? Theorem. The bisector of an- angle of a triangle divides the...segments which are proportional to the adjacent sides. A Data: Any triangle, as ABC, and CD the bisector of one of its angles, ACB. To prove AD : DB = AC...
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