...conversely, the greater angle is opposite the greater side. 2.- Show that in any continued proportion, the sum of the antecedents is to the sum of the consequents as any antecedent to its corresponding consequent. 3. Prove that, in equal circles, incommensurable angles at the centre...

...composition, (л By division, iZ=°ri (2) Dividing (1) by (2), we have, a + b _c + d a — b с — d 292. IX. In a Series of Equal Ratios the sum of the antecedents...consequents as any antecedent is to its consequent. If a:b = c:d = e:f=g:h. To prove (a + b + e + g) : (b + d +f+ K)=a:b. If a:b=c:d = e:f=g:h, н=нALGEBPA....

...(232") PROPOSITION XII. THEOREM. 251. If any number of like quantities are in continued proportion, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent. Given : A : B = C : D = K : V ; To Prow : A + C + E : B + D + F = A : B. Since a:b = c:d = e:f, (Hyp....

...+ d : c - d. as. D. PROPOSITION IX. 303. In a series of equal ratios, the sum of the an~ tecedents is to the sum of the consequents as any antecedent is to its consequent. Let a:b = c:d = e :/= g : ft. To prove a + c + e+^r : 6+<f+/+ h = a : b. Denote each ratio by r. N...

...ab or - = -• с d .'. a : с = b : d. 317. In a series of equal ratios, the sum of the antecedent? is to the sum of the consequents as any antecedent is to its consequent. n • » a с ea For, if _ = - = - = £, oafп r may be put for each of these ratios. rm.™ a_ r c_.-r...

...= -> = 7. , each of these ratios = , - =- . • b 9 f b+d+f a result which may be thus enunciated : In a series of equal ratios the sum of the antecedents is to ¡he sum of the consequents as any antecedent is to its consequent. Example. 1. If - = — find tho...

...the first two terms is to their difference as the sum of the last two terms to their difference. 303. In a series of equal ratios, the sum of the antecedents...consequents as any antecedent is to its consequent. 304. The products of the corresponding terms of two or more proportions are in proportion. 305. Like...

...obtained by: VI. Composition, и --\- c : c : : b + d : d. VII. Division. « — c:c::b — d : d. 350. In a series of equal ratios, the sum of the antecedents...sum of the consequents as any antecedent is to its т-. -taceg For-lf b = d = J=V r may be put for each of these ratios. , ., aeeg Then - = f,- = r,j=r,0...

...equations ma me multiplying as ot fractions a _ c PROPOSITION VIII 195. Theorem. In a continued proportion, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent. Let ————-- b~d~f'~ ['value of each ratio e=fr ,.] clearing of fractions separately a + c +...

...Dividing (1) by (2), member by member, _ ab~cd' that is, о + b • a — b = с + d : с — d. 530. In a series of equal ratios, the sum of the antecedents is tc the sum of the consequents as any antecedent is toits consequent. ï-ï-i-7-î' then, by § 522,...