AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
| George Gordon Byron Baron Byron - 1866 - 292 pages
...wonder how the devil he came there." The trio are well defined in the sixth proposition of Euclid: "Because, in the triangles DBC, ACB, DB is equal to AC, and BC common to both; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC... | |
| Henry Major - Student teachers - 1873 - 580 pages
...greater: let AB be the greater- and from it cut off BD equal to AC the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC, are equal to the two AC, CB, each to each; and the angle DBC... | |
| Edward Atkins - 1874 - 426 pages
...AB, the greater, cut off a part DB, Make equal to AC, the less (I. 3). ' DB=AC. Join DC. PROOF. — Because in the triangles DBC, ACB, DB is equal to...Therefore the two sides DB, BC are equal to the two sides AC, CB, each to each ; And the angle DBC is equal to the angle ACB (Hyp.) Therefore the base... | |
| Edward Atkins - 1876 - 130 pages
...AB, the greater, cut off a part DB, jiak« equal to AC, the less (I. 3). WJ = AI Join DC. PROOF. — Because in the triangles DBC, ACB, DB is equal to...both, Therefore the two sides DB, BC are equal to the t\vo sides AC, CB, each to each • y\ And the angle DBC is equal to the angle ACB (Hyp.) Therefore... | |
| Elias Loomis - Conic sections - 1877 - 458 pages
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DBC, ACB, DB is equal to AC, and BC is common to both triangles, also, by supposition, the angle DBC is equal to the angle ACB ; therefore the triangle DBC... | |
| Edward Atkins - 1877 - 72 pages
...AC, the less (I. 3). Join DC. PROOF. — Because in the triangles DBC, ACL, DB is equal to AC, and EC is common to both, Therefore the two sides DB, BC are equal to the two sides AC, CB, each to each ; And the angle DBC is equal to the angle ACB (Hyp.) Therefore the base... | |
| Isaac Brandon - 1811 - 598 pages
...Becanse, in the triangles DEC, ACB, DB is equal t .i AC, and BC common to both ; the two side* 1) li, BC, are equal to the two AC, CB, each to each, and the angle DBC is equal to the angle ACB : therefore, the base DC is equal to the haee AB, and the triangle... | |
| Elias Loomis - 1880 - 456 pages
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DBC, ACB, DB is equal to AC, and BC is common to botli triangles, also, by supposition, the angle DBC is equal to the angle ACB ; therefore the triangle... | |
| Walter Percy Workman - 1880 - 248 pages
...and from it cut off DB equal to AC the less, [i. 3 and join DC. Then because in the triangles DEC, ACB, DB is equal to AC, and BC is common to both, the two sides DB, BC are equal to the two sides AC, CB, each to each ; and the angle DBC is equal to... | |
| Stewart W. and co - 1884 - 272 pages
...greater ; let AB be the greater, and from it cut off BD equal to AC the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC, are equal to the two AC, CB, each to each ; and the angle DBC... | |
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