AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
| George Gordon N. Byron (6th baron.) - 1885 - 268 pages
...rare, Euclid: — "Because, in the triangles DBC, ACB, I) H is equal to AC, and BC common to both ; **the two sides DB, BC, are equal to the two AC, CB, each to each, and the** angle DBC is equal to the angle ACB : therefore, the base DC is equal to the base AB, and the triangle... | |
| George Gordon Byron Baron Byron - 1918 - 568 pages
...proposition of Euclid :— " Because, in the triangles DEC, ACB;DB is equal to AC ; and BC common to both ; **the two sides DB, BC, are equal to the two AC, CB, each to** ench, and the angle DBC is equal to the angle ACB : therefore, the base DC is equal to the base AB,... | |
| 164 pages
...equal to the less AC; and let DC be joined, (v) Then since DB is equal to AC, and BC is common, the two **DB, BC are equal to the two AC, CB, each to each ; and the** angle DBC is equal to the angle ACB. Therefore the base DC is equal to the base AB; and the triangle... | |
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