 AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle...  Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
 | George Gordon N. Byron (6th baron.) - 1885 - 268 pages
...rare, Euclid: — "Because, in the triangles DBC, ACB, I) H is equal to AC, and BC common to both ; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC is equal to the angle ACB : therefore, the base DC is equal to the base AB, and the triangle... | |
 | George Gordon Byron Baron Byron - 1918 - 568 pages
...proposition of Euclid :— " Because, in the triangles DEC, ACB;DB is equal to AC ; and BC common to both ; the two sides DB, BC, are equal to the two AC, CB, each to ench, and the angle DBC is equal to the angle ACB : therefore, the base DC is equal to the base AB,... | |
 | 164 pages
...equal to the less AC; and let DC be joined, (v) Then since DB is equal to AC, and BC is common, the two DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to the angle ACB. Therefore the base DC is equal to the base AB; and the triangle... | |
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