AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
| George Gordon Byron Baron Byron - 1866 - 292 pages
...wonder how the devil he came there." The trio are well defined in the sixth proposition of Euclid: **"Because, in the triangles DBC, ACB, DB is equal to AC, and BC** common to both; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC... | |
| Henry Major - Student teachers - 1873 - 588 pages
...greater: let AB be the greater- and from it cut off BD equal to AC the less, and join DC ; therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides DB, BC, are equal to the two AC, CB, each to each; and the angle DBC... | |
| Edward Atkins - 1874 - 426 pages
...AB, the greater, cut off a part DB, Make equal to AC, the less (I. 3). ' DB=AC. Join DC. PROOF. — **Because in the triangles DBC, ACB, DB is equal to...Therefore the two sides DB, BC are equal to the two** sides AC, CB, each to each ; And the angle DBC is equal to the angle ACB (Hyp.) Therefore the base... | |
| Edward Atkins - 1876 - 130 pages
...AB, the greater, cut off a part DB, jiak« equal to AC, the less (I. 3). WJ = AI Join DC. PROOF. — **Because in the triangles DBC, ACB, DB is equal to...both, Therefore the two sides DB, BC are equal to the** t\vo sides AC, CB, each to each • y\ And the angle DBC is equal to the angle ACB (Hyp.) Therefore... | |
| Elias Loomis - Conic sections - 1877 - 458 pages
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, **because in the triangles DBC, ACB, DB is equal to AC, and BC is common to both** triangles, also, by supposition, the angle DBC is equal to the angle ACB ; therefore the triangle DBC... | |
| Edward Atkins - 1877 - 72 pages
...AC, the less (I. 3). Join DC. PROOF. — Because in the triangles DBC, ACL, DB is equal to AC, and EC **is common to both, Therefore the two sides DB, BC are equal to the two** sides AC, CB, each to each ; And the angle DBC is equal to the angle ACB (Hyp.) Therefore the base... | |
| Isaac Brandon - 1811 - 598 pages
...Becanse, in the triangles DEC, ACB, DB is equal t .i AC, and BC common to both ; the two side* 1) li, **BC, are equal to the two AC, CB, each to each, and the** angle DBC is equal to the angle ACB : therefore, the base DC is equal to the haee AB, and the triangle... | |
| Elias Loomis - 1880 - 456 pages
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, **because in the triangles DBC, ACB, DB is equal to AC, and BC is common to** botli triangles, also, by supposition, the angle DBC is equal to the angle ACB ; therefore the triangle... | |
| Walter Percy Workman - 1880 - 248 pages
...and from it cut off DB equal to AC the less, [i. 3 and join DC. Then because in the triangles DEC, **ACB, DB is equal to AC, and BC is common to both,** the two sides DB, BC are equal to the two sides AC, CB, each to each ; and the angle DBC is equal to... | |
| Stewart W. and co - 1884 - 272 pages
...greater ; let AB be the greater, and from it cut off BD equal to AC the less, and join DC ; therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides DB, BC, are equal to the two AC, CB, each to each ; and the angle DBC... | |
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