AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
| George Gordon Byron Baron Byron - 1847 - 880 pages
...proposition of Euclid : " Because, in the triangles DEC, AC B, DB Is equal to AC, and BC common to both ; **cy, in iU excursions, could collect ; and, how little fettered he was b** angle DBC is equal to the angle ACS: therefore, the base DC is equal to the base AB. and the triangle... | |
| Elias Loomis - Conic sections - 1849 - 252 pages
...than the other. Let AB be the greater, and from it cut off DB equal to AC the less, and join CD. Then, **because in the triangles DBC, ACB, DB is equal to AC, and BC is common to both** triangles, also, by supposition, the angle DBC is equal to the angle ACB; therefore, the triangle DBC... | |
| Euclid, Thomas Tate - 1849 - 120 pages
...let AB be the greater, and from it cut (i. 3.) off DB equal to AC, the less, and join DC.; therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is... | |
| Euclides - 1852 - 152 pages
...AB be the greater; " i'i, '. and from it cut" off DB equal to AC, the less, and join DC; Therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides, DB, BC are equal to the two AC, CB, each to each; and the angle DBC... | |
| Royal Military Academy, Woolwich - Mathematics - 1853 - 400 pages
...; therefore, because in the triangles DBC, ACB, DB is equal to AC (Constr.), and BC common to both, **the two sides, DB, BC are equal to the two AC, CB, each to each ; and the** angle DBC is equal to the angle (Hyp.) ACB; therefore the base DC is equal to the base AB, and I he... | |
| Euclides - 1853 - 146 pages
...Let AB be the greater, and from it cut off (I. 3.) DB equal to AC, the less, and join DC. Therefore **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, 1. The two sides DB, BC, are equal to the two AC, CB, each to each; and the angle DBC... | |
| George Gordon Byron Baron Byron - 1854 - 1126 pages
...proposition of Euclid : " Because, In EBB triangles DBC, ACB, DB Is equal to AC, anil EC, common to both ; **the two sides DB, BC, are equal to the two AC, CB, each to each, and the** angle DEC ij equal to the angle ACB : therefore, tí» tuse DC Is equal to the base AB, aüd the triangle... | |
| George Gordon Byron Baron Byron - 1854 - 1104 pages
...Euclid : " Became, In S» trungVi DBC, ACB, RB is equal to AC, nnd BC, common to both ; the пим^-tDB, **BC, are equal to the two AC, CB, each to each, and the** angle Dû: л nfxil to the angle ACB : therefore, the baae DC la equal to the bue A3, ind tb, triangle... | |
| Elias Loomis - Conic sections - 1858 - 256 pages
...greater, and from it cut off DB equal to AC the less, and join CD. Then, because in the triangles DEC, **ACB, DB is equal to AC, and BC is common to both** triangles, also, by supposition, the angle DBG is equal to the angle ACB ; therefore, the triangle... | |
| Euclides - 1862 - 172 pages
...Then in the triangles DEC, ACB, because DB is assumed to be equal to AC, and BC is common to both, **the two sides DB, BC, are equal to the two AC, CB, each to each -, and the** angle DBC is equal to the angle ACB ; (hyp.) therefore the base DC must be equal to the base AB, and... | |
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