AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
| Euclid - Geometry - 1810 - 554 pages
...and join DC; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, **the two sides DB, BC are equal to the two AC, CB, each to each; and the** angle DBC is equal to the angle ACB; therefore the base DC is equal to the base AB, and the triangle... | |
| Euclides - 1816 - 592 pages
...be the greater ; and from it cut" • 3. 1. off DB equal to AC, the less, and join DC; therefore, , **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the twosides, DB, BC are equal to the two AC, CB each to each ; and the angle DBC is... | |
| John Playfair - Circle-squaring - 1819 - 348 pages
...join DC ; therefore, be- cause in the triangles DBC, ACB, DB is equal to AC, and BC common to both, **the two sides DB, BC are equal to the two AC, CB, each to each** ; but the angle DBC is also equal to the angle ACB ; therefore the base DC is equal to the base AB,... | |
| John Playfair - 1819 - 354 pages
...greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, be- * cause **in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
| Adrien Marie Legendre - Geometry - 1822 - 394 pages
...are not equal, let AB be the greater. Take BD=AC, and join DC. The angle DBC is (Hyp.) equal to ACB ; **the two sides DB, BC, are equal to the two AC, CB,** by construction ; therefore (Prop. 6.), the B triangle DEC must be equal to ACB. But the part cannot... | |
| Peter Nicholson - Mathematics - 1825 - 1058 pages
...Let AB be the greater; and from it cut (3. 1.) off DB equal AC, the less, and join DC ; therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both the two sides, DB,BC, are equal to the two AC, CB each to each ; and the angle DBC is... | |
| Robert Simson - Trigonometry - 1827 - 546 pages
...AB be the greater ; and * 3. 1. from it cut * off DB equal to AC, the less, and join DC : therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides, DB, BC are equal to the two AC, CB, each to ' 4. 1. each; and the angle... | |
| George Gordon Byron Baron Byron - 1831 - 498 pages
...proposition of Euclid : *« Because, in the triangles DBC.ACB, DB is equal to AC, and BC, common to both; **the two sides DB, BC, are equal to the two AC, CB, each to each, and the** angle DBC Is equal to the angle ACB : thereThough « Madoc," with " Pucelle */' instead of Punch, May... | |
| George Gordon Byron Baron Byron, Thomas Moore - Poets, English - 1832 - 394 pages
...wonder how the devil he came there." The trio are well defined in the sixth proposition of Euclid : " **Because, in the triangles DBC, ACB, DB is equal to AC, and BC** common to both ; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC... | |
| George Gordon Byron Baron Byron, Thomas Moore - Poets, English - 1832 - 384 pages
...wonder how the devil In. came there." The trio are well defined in the sixth proposition of Euclid : " **Because, in the triangles DBC, ACB, DB is equal to AC, and BC** common to both ; the two sides DB, BC, are equal to the two AC, CB, each to each, and the angle DBC... | |
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