 | George Bruce Halsted - Geometry - 1885 - 389 pages
...basal radii rl and r2 find the radius of the circle in which the two cones cut. 329 THEOREM III. 832. The lateral area of a frustum of a cone of revolution is the product of the projection of the frustum s slant height on the axis by twice TT times a perpendicular... | |
 | George Bruce Halsted - Geometry - 1886 - 394 pages
...basal radii r, and r, find the radius of the circle in which the two cones cut. 329 THEOREM III. 832. The lateral area of a frustum of a cone of re-volution is the product of the projection of the frustums slant height on the axis by twice ?r times a perpendicular... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...by its slant height. Corollary I. This proposition may be formulated, tf=ir(JB + r}L. Corollary II. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. PROPOSITION... | |
 | William Chauvenet - Geometry - 1889 - 338 pages
...r)L, if R and r are the radii of the bases and L is the slant height. A ^"• 27. COROLLARY II. Tlie lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. Suggestion.... | |
 | Edward Albert Bowser - Geometry - 1890 - 414 pages
...squares of their radii, or of their slant heights, or of their altitudes. Proposition 6. Theorem. 776. The lateral area of a frustum of a cone of revolution is equal to half the sum of the circumferences af its bases multiplied by its slant height. Hyp. Let S, C, c, L denote the lateral area of the frustum,... | |
 | Edward Albert Bowser - Geometry - 1890 - 418 pages
.... L' and S' will approach L and S respectively, as their limits. . • . S = i(C + c)LQED 777. COR. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases* multiplied by its slant height. * Called... | |
 | Edward Albert Bowser - Geometry - 1890 - 420 pages
...and S' will approach L and S respectively, as their limits. . • . S = i|(C + c)LQED 777. COR. TJie lateral area of a frustum of a cone of revolution is equal to the circumference of a sect ion equidistant from its bases* multiplied by its slant height. * Called... | |
 | George Albert Wentworth - Geometry - 1888 - 466 pages
...lateral faces of the frustum of the pyramid, s = $(P+p)xL. .'.#=£ ((7+ c)X£. §260 QED 676. COR. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. PROPOSITION... | |
 | William Chauvenet - 1893 - 340 pages
...S = n(R -\- r)L, if R and r are the radii of the bases and L is the slant height. 27. COROLLARY II. The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. Suggestion.... | |
 | Arthur Latham Baker - Geometry, Solid - 1893 - 154 pages
...sum of the faces = S = \ l X sum of the perimeters of the bases = £ I (/>+.pi). p.. ED 154. COR. 1. The lateral area of a frustum of a cone of revolution is equal to the product of the slant height by one half the sum of the circumferences of the buses. 155. COR. 2.... | |
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The lateral area of a frustum of a cone of revolution is equal to the circumference of a section equidistant from its bases multiplied by its slant height. 
