| Daniel Adams - 1839 - 268 pages
...the foregoing example and illustration we derive the following RULE FOR EXTRACTING T1IK CUBE ROOT. **I. Separate the given number into periods of three...and every third figure beyond the place of units.** II. Find the greatest cube in the left hand period, and put its root in the quotient. III. Subtract... | |
| Benjamin Greenleaf - Arithmetic - 1839 - 305 pages
...number can never contain more than three times that number, and at least but two less. We therefore **separate the given number into periods of three figures...figure, and every third figure beyond the place of units** ; thus 46.656. We find by the table of powers the greatest power in the left hand period, 46 (thousand)... | |
| Nathan Daboll - 1839
...and 2 feet thick, is 2x2x2=8 cubic feet. Hence the cube root of 8 is 2, because 23, that is, 2x2x2=8. **RULE. I. Separate the given number into periods of...point over the unit figure, and every third figure** from the place of units, towards the left, and if there be decimals, point them from the unit's place... | |
| Daniel Adams - Arithmetic - 1840 - 264 pages
...From the foregoing example and illustration we derive the following RULE FOR EXTRACTJNS THE CUBE ROOT. **I. Separate the given number into periods of three...and every third figure beyond the place of units.** II. Find the greatest cube in the left hand period, and put its root in the quotient. III. Subtract... | |
| Benjamin Greenleaf - Arithmetic - 1841 - 314 pages
...number can never contain more than three times that number, and at least but two less. We therefore **separate the given number into periods of three figures...figure, and every third figure beyond the place of units** ; thus 46.656. We find by the table of powers the greatest power in the left hand period, 46 (thousand)... | |
| Benjamin Greenleaf - Arithmetic - 1842 - 186 pages
...20 2940 Cube of 7 343 Hence the following RULE. figure beyond the place of units. Proof. = 19683. 1. **Separate the given number into periods of three figures...putting a point over the unit figure, and every third** 2. Find by the table the greatest cube in the left hand period, and put its root in the quotient. 3.... | |
| Nathan Daboll - Arithmetic - 1842 - 270 pages
...multiplied into its square, shall produce the given number. RULE. 1. Separate the given number in4o **periods of three figures each, by putting a point over the unit figure, and every third figure** from the place of units to the laft, and if there be decimals, to the right. 2. Find the greatest cube... | |
| Charles Davies - Algebra - 1842 - 368 pages
...root of 43725658, to within unity. Hence, for the extraction of the cube root we have the following **RULE. I. Separate the given number into •periods of three figures each,** beginning at the right hand: the left hand period will often contain less than three places of figures.... | |
| Nathan Daboll - Arithmetic - 1843 - 254 pages
...2 feet thick, is 2x2x2=8 cubic feet. Hence the cube root of 8 is 2, because 23, that is, 2X2 x2=8. **RULE. I. Separate the given number into periods of...putting a point over the unit figure, and every third** rigure from the place of units, towards the left, and if there be decimals, point them from the unit's... | |
| Benjamin Greenleaf - Arithmetic - 1843 - 314 pages
...root, is to find a number, which, multiplied into its square, will produce the given number. RULE. 1 . **Separate the given number into periods of three figures...putting a point over the unit figure, and every third** Jigure beyond the place of units. 2. Find by th.e table the greatest cube in the left hand period,... | |
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