| John Blenkarn - Forests and forestry - 1859 - 300 pages
...and multiply by the diagonal — half the product will be the area. To find the area of a circle : Multiply the square of the diameter by '7854, and the product will be the arae. SECTION V. ON THE MEASUREMENT AND VALUATION OF STANDING TIMBER. FORM OF FIELD-BOOK WITH TABLES,... | |
| Alfred Newsom Niblett - 1861 - 204 pages
...area. Or, divide the product of the whole circumference and diameter by 4, and the quotient will be the area. 2. Multiply the square of the diameter by -7854, and the product will be the area. 3. Multiply the square of the circumference by -07958, and the product will be the area. PROBLEM 10. To... | |
| Oliver Byrne - Engineering - 1863 - 600 pages
...15-75 = \ circumference. 5 3 = 5-25 = J diameter. 7875 3150 7875 82-6875 12 8-2500 82 feet 8 inches. Multiply the square of the diameter by -7854, and the product will be the area ; or, Multiply the square of the circumference by -07958, and the product will be the area. The following... | |
| A. C. Smeaton - Building - 1867 - 314 pages
...circumference by half the diameter, and the product will be the area. 2. When the diameter is given. RULE. Multiply the square of the diameter by .7854, and the product will be the area. 3. When the circumference is given. RULE. Multiply the square of the circumference by .07958, and the... | |
| Moffatt and Paige - 1879 - 506 pages
...Multiply half the circumference by half the diameter, and the product will be the area required. (b) Multiply the square of the diameter by 7854, and the product will be the area. Proof. — These rules can only be fully proved by Trigonometry. It may, however, be observed that... | |
| Frederick Thomas Hodgson - Carpentry - 1883 - 174 pages
...circumference by half the diameter, and the product will be the area. 2. When the diameter is given. Rule. — Multiply the square of the diameter by 7854, and the product will be the area, or the diameter by the circumference and divide by 4. 3. When the circumference is given. To Find the... | |
| Simpson Bolland - 1893 - 420 pages
...OPERATION. Decimal multiplier 31831 Circumference 45 159155 127324 TO FIND THE AREA OF A CIRCLE. Rule. — Multiply the square of the diameter by .7854 and the product will be the area. Note. — The square of any number is that number multiplied by itself, as .12 x 12 — 144, etc. Example.... | |
| Simpson Bolland - Iron founding - 1893 - 420 pages
...45 159155 127324 Diameter required 1 4.3 2 3 9 5 feet, ans. TO FIND THE AREA OF A CIRCLE. Rule. — Multiply the square of the diameter by .7854 and the product will be the area. Note. — The square of any number is that number multiplied by itself, as 12 x 12 = 144, etc. Example.... | |
| Clement Mackrow - Naval architecture - 1916 - 766 pages
...Y = the required ordinate, then y = VB2-xa - E + v. 11. To find the area of a circle. EULE (I). — Multiply the square of the diameter by '7854, and the product will equal the area, nearly. Thus if A = the area, D = the diameter, then A = D2 X '7854. BULK (TI). —... | |
| William Miller Barr - Engineering - 1918 - 650 pages
...of a circle is equal to half the circumference multiplied by the radius, or half the diameter. Rule 2. Multiply the square of the diameter by .7854, and the product will be the area; or, multiply the square of the circumference by .07958, and the product will bo the area. NOTE. —... | |
| |