 | 458 pages
...125 ft. 8 in. nearly = arc. PROBLEM XII. To find the area of a circle. 1. When the diameter is given, multiply the square of the diameter by .7854, and the product will be the area. 2. When the circumference and diameter both are given, multiply half the circumference by half the... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...diameter of a circle whose circumference is 128 feet? PROBLEM XIX. To find the area of a circle. RULE. Multiply the square of the diameter by .7854, and the product will be the area. Or multiply the square of the circumference by .07958, and the product will be the area. EXAMPLES.... | |
 | Thomas Tate (mathematical master.) - 1848 - 284 pages
...half the circumference by half the diameter, and the product will be the area. (See Geo. Art. 75.) 2. Multiply the square of the diameter by -7854, and the product will be the area. (See Trigo. Art. 34.) Note. If the area be divided by -7854, the quotient will be the square of the... | |
 | John Bonnycastle - Geometry - 1848 - 320 pages
....7854. 4. What is the area of a circle whose diameter is 7, and circumference 22 ? Ans. 38£, RULE II.* Multiply the square of the diameter by .7854, and the product will be the area ; or, Multiply the square of the circumference by ,07958, and the product will be the area. * Demon.... | |
 | John Radford Young - Measurement - 1850 - 294 pages
...L Multiply half the circumference by half the diameter and the product will be the area. RULE. II. Multiply the square of the diameter by '7854, and the product will be the area. NOTE .— From these rules, it follows :— 1. That the square of half the circumference divided by... | |
 | Oliver Byrne - Engineering - 1851 - 310 pages
...15-75 = J circumference. 5 3 = 5-25 == £ diameter. 7875 3150 7875 82-6875 12 8-2500 82 feet 8 inches. Multiply the square of the diameter by -7854, and the product will be the area ; or, Multiply the square of the circumference by -07958, and the product will be the area. The following... | |
 | Jeremiah Joyce - Science - 1852 - 430 pages
...is sufficiently accurate for all common purposes. 12. The area of a circle is found by multiplying the square of the diameter by .7854, and the product will be the area. Example. — What is the area of a circle whose diameter is SO yards. Ans. .7854 + 50* = .7854 X 2500... | |
 | Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...63, and the diameter' 20 rods ? Ans. 315. Art. 274* — The diameter given, to find the area. RULE. Multiply the square of the diameter by .7854, and the product will be the area. 1. What is the area of a circle whose diameter is 28 rods? 28 x 28 x. 7854 = 615. 7536 rods, Ans. 2,... | |
 | Anthony Nesbit - Measurement - 1859 - 494 pages
...area. Or, divide the product of the whole circumference and diameter by 4, and the quotient will be the area. 2. Multiply the square of the diameter by .7854, and the product will be the area. 3. Multiply the square of the circumference by .07958, and the product will be the area. Note 1 If the... | |
 | Charles Guilford Burnham - 1859 - 338 pages
...63, and the diameter 20 rods ? Ans. 315. Art. 274, — The diameter given, to find the area. •RULE. Multiply the square of the diameter by .7854, and the product will be the area. 1. What is the area of a circle whose diameter is 28 rods ? 28 X 28 X. 7854=615.7536 rods, Ans. 2,... | |
| |
... multiply the square of the diameter by ,7854 and the product will be- the area. 
