 | Tobias Ostrander - Measurement - 1834 - 182 pages
...what is its diameter 1 Ans. 5,2521 feet. PROBLEM III. The diameter given, to find the area. Rule — Multiply the square of the diameter by ,7854, and the product will be the area. EXAMPLES. 1. The diameter of a circle is 16 chains — How many acres are contained within its periphery... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...circumference is 63, and the diameter 20 rods ? Answer, 315 rods. The diameter given, to find the area. RULE. Multiply the square of the diameter by ,7854, and the product will be the area. 1. What is the area of a circle whose diameter is 28 rods? 28 X 28 X, 7854=615,7536 rods, Answer. 2.... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...circumference, and the product is the area ; or if the diameter U given without the circumference, multiply the square of the diameter by ,7854 and the product will be the area. EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches.... | |
 | Nathan Daboll - 1839 - 220 pages
...RULE. Multiply half the diameter by half the circumference, and the pro. duct will be the area. Or, multiply the square of the diameter by ,7854, and the product will be the area. 1. Required the area of a circle whose diameter is 21 inches, and circumference 66 inches ? J circumference... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...RULE. 1. Multiply half the circumference by half the diameter, and the product will be the area. Or multiply the square of the diameter by .7854, and the product will be the area. Or multiply the square of the circumference by .07958, and the product will be the area. 2. Divide... | |
 | Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...circumference is 63, and the diameter 20 rods? Answer, 315 rods. The diameter given, to find the area. RULE. Multiply the square of the diameter by .7854, and the product will be the area. 2. What is the area of a circle whose diameter is 59 rods ? Answer, 2733.9774 rods. The circumference... | |
 | William Ruger - Arithmetic - 1841 - 268 pages
...7 poles. •y*s *%« 1**. s€"a To find the area of a circle, the diameter being given, RULE. — Multiply the square of the diameter by ,7854, and the product will be the area. Or multiply half the diameter by half the circumference, and the product will be the area. EXAMPLES.... | |
 | Nathan Daboll - 1843 - 260 pages
...circumferencei and the product is the area; or if the diameter is give* without the circumference, multiply the square of the diameter by ,7854 and the product will be the area. EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches.... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 pages
...enable the plumber or mechanic to find the number of gallons that a pump will lift per stroke. RULE. — Multiply the square of the diameter by .7854, and the product will be the area of the circle or bottom in square inches. Multiply this area by the depth of the vessel in inches,... | |
 | Nathan Scholfield - 1845 - 894 pages
...circle re quired. Or thus : 31.4159 x^ =78.5398 as before. RULE II. — When the diameter only is given. Multiply the square of the diameter by .7854, and the product will be the area of the circle. For the ratio of the square described on the diameter of a circle, is to the circle'*... | |
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... multiply the square of the diameter by ,7854 and the product will be- the area. 
