 | William Smyth - Algebra - 1858 - 344 pages
...From what has been done we have the following rule for the multiplication of polynomials, viz. 1°. Multiply each term of the multiplicand by each term of the multiplier, observing with respect to the signs, that if two terms multiplied together have each the same sign,... | |
 | Isaac Todhunter - Algebra - 1858 - 530 pages
...considering the above cases we arrive at the following rule for multiplying two binomial expressions. Multiply each term of the multiplicand by each term of the multiplier; if the terms have the same sign, prefix the sign + to the product, if they have different signs prefix... | |
 | James B. Dodd - Arithmetic - 1859 - 368 pages
...RULE XXXI. (132.) To Multiply one Duodecimal Polynomial by another. 1. Proceeding from right to left, multiply each term of the multiplicand by each term of the multiplier; mark each product term with the proper index (131), and set similar terms one under another. 2. When... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 362 pages
...I. Write the several terms of the multiplier tinder the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier, beginning with the lowest term in each, and call the product of any two denominations the denomination... | |
 | John Fair Stoddard, William Downs Henkle - Algebra - 1859 - 538 pages
...Yaarjyd — Haxy~*c. CASE III. (91.) When both the multiplicand and multiplier are polynomials. RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the products. PROBLEM. Multiply a' + 06 + 6* by a + 6. SOLUTION. Operation. a*+ a6 + 6' Multiplying... | |
 | Philip Kelland - 1860 - 308 pages
...Propositions of the Second Book. 9. (a' - 62) x 5 (a2 + b') = 5 (a4 - 64) = 5al - 5b\ 10. (a- b + c) (a + be). Multiply each term of the multiplicand by each term of the multiplier, arranging the results as below : a — b + c a + b — c a' — ab + ac + ab - 62 + be — ac + be... | |
 | James Bates Thomson - Arithmetic - 1860 - 440 pages
...1. Place the several terms of the multiplier under the corresponding terms of the multiplicand. II. Multiply each term of the multiplicand by each term of the multiplier separately, beginning with the lowest denomination in the multiplicand, and the highest in the multiplier,... | |
 | Benjamin Greenleaf - 1863 - 338 pages
...of these 1 ' partial products is 3o? -\- 5ab -\- 2W; the required product. Hence the following RULE. Multiply each term of the multiplicand by each term of the multiplier separately, and add the partial products. EXAMPLES. (2.) (3.) 4a-f-3ft 5 ж 4- 3У 3а -\- bx — 2y... | |
 | George Augustus Walton - Arithmetic - 1864 - 364 pages
...term by which we multiply. The sum of these part:^ products is the entire product. Hence the RULE FOB MULTIPLICATION. Write the multiplier under the multiplicand....partial product Under the term by which you multiply, car* rying as in addition. Add all the partial products, and tlie result will be the entire product.... | |
 | George Augustus Walton, Mrs. Electra Nobles Lincoln Walton - Arithmetic - 1865 - 354 pages
...MULTIPLICATION. Write the multiplier under the multiplicand, units under units, tens under tens, etc. Beginning at the right, multiply each term of the...right hand figure of each partial product under the figure by which you multiply, carrying as in addition. Add all the partial products, and the result... | |
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In the multiplication of whole numbers, place the multiplier under the multiplicand, and multiply each term of the multiplicand by each term of the multiplier, writing the right-hand figure of each product obtained under the term of the multiplier which... 
