 | Roswell Park - Best books - 1841 - 624 pages
...bounded by three arcs of great circles, that is, circles whose planes pass through the centre. The convex surface of a cylinder, is equal to the circumference of its base, multiplied by its altitude : that of a cone, is equal to the circumference of its base, multiplied by its slant height, or distance... | |
 | Adrien Marie Legendre - Geometry - 1841 - 288 pages
...cylinder is less than that of any cirn^. 253. cumscribed prism BCDKLH (fig. 253). THEOREM. 523. The convex surface of a cylinder is equal to the circumference of its base multiplied by its altitude. Fig. 253. Demonstration. Let CA (fig. 258) be the radius of the base of the given cylinder, H its altitude... | |
 | James Bates Thomson - Geometry - 1844 - 268 pages
...equal to its perimeter multiplied by its altitude AF ; (5. 7 ;) therefore the convex surface of the cylinder is equal to the circumference of its base multiplied by its altitude ; that is, equal to cire. RCxH. Hence, The convex surface of a cylinder is equal, $e. PROPOSITION II.... | |
 | Nathan Scholfield - 1845 - 894 pages
...perimeter of its base multiplied by H, whatever be the number of sides : hence, the convex surface of the cylinder is equal to the circumference of its base multiplied by its altitude. PROPOSITION II. THEOREM. The solidity of a cylinder is equal to the product of its base by its altitude.... | |
 | Nathan Scholfield - Geometry - 1845 - 506 pages
...will be divided in the ratio that the circumference of the base is divided. But the convex surface is equal to the circumference of its base multiplied by its altitude. (Prop. IB III. El. S. Geom.,) and its solidity is equal to the area of its base multiplied by its altitude,... | |
 | Nathan Scholfield - Conic sections - 1845 - 542 pages
...will be divided in the ratio that the circumference of the base is divided. But the convex surface is equal to the circumference of its base multiplied by its altitude, (Prop. IB III. El. S. Geom.,) and its solidity is equal to the area of its base multiplied by its altitude,... | |
 | George Roberts Perkins - Geometry - 1847 - 326 pages
...might be shown to be less than that of any circumscribed prism BCDKLKH. PROPOSITION IV. THEOREM. The convex surface of a cylinder is equal to the circumference...altitude ; the circumference whose radius is CA being re- | presented by circ. CA, we are to show that circ. CA XH will be the convex surface of the cylinder.... | |
 | Roswell Park - Best books - 1847 - 626 pages
...bounded by three arcs of great circles, that is, circles whose planes pass through the centre. The convex surface of a cylinder, is equal to the circumference of its base, multiplied by its altitude : that of a cone, is equal to the circumference of its base, multiplied by its slant height, or distance... | |
 | George Roberts Perkins - Geometry - 1850 - 332 pages
...might be shown to be less than that of any circumscribed prism BCDKLKH. PROPOSITION IV. THEOREM. The convex surface of a cylinder is equal to the circumference...being represented by circ. CA, we are to show that circ. CA x H will be the convex surface of the cylinder. For, if this proposition be not true, then... | |
 | Charles Davies - Geometry - 1850 - 218 pages
...convex surface is still equal to the perimeter of its base multiplied by its altitude : hence, the convex surface of a cylinder is equal to the circumference of its base multiplied by its altitude. THEOREM III. In every prism the sections formed by planes parallel to the base are equal polygons.... | |
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The convex surface of a cylinder is equal to the circumference of its base multiplied by its altitude, Fig. 
