 | 1884 - 266 pages
...equal to two right angles. 3. If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal...section, is equal to the square of half the line. 4. A segment of a circle being given, describe the circle of which it is the segment. "5. On a base... | |
 | Stewart W. and co - 1884 - 272 pages
...unequal parts ; the rectangle contained by tlte unequal parts, together with the square of the Une between the points of section, is equal to the square of half the line. Let AB be divided into two equal parts in the point C, and into two unequal parts in the point D : then... | |
 | Woolwich roy. military acad - 1884 - 148 pages
...intersect at right angles to one another. 5. If a straight line be divided into two equal and also two unequal parts, the rectangle contained by the unequal parts together with the square on the line between the points of section is equal to the square on half the line. If of the two unequal... | |
 | George Bruce Halsted - Geometry - 1885 - 389 pages
...and for DC put b, we get the theorem : If a sect is divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equivalent to the square on half the sect. 297. If CD... | |
 | Oxford univ, local exams - 1885 - 358 pages
...than the base of the other. 4. If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 5. If a side of... | |
 | United States. Congress. Senate - United States - 1880 - 1302 pages
...(.'/•' pa>-« through A. '¿. If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. Prove that the... | |
 | Dalhousie University - 1886 - 216 pages
...divided into two equal and also into two unequal parts, the rectangle contained by the two latter, together with the square of the line between the points...section, is equal to the square of half the line. (Best, by the division of the line.) 3. Deduce from the last problem, and express in words, the proposition... | |
 | George Bruce Halsted - Geometry - 1886 - 394 pages
...and for DC put b, we get the theorem : If a sect is divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equivalent to the square on half the sect. 297. If CD... | |
 | Dalhousie University - 1887 - 206 pages
...themselves equal and parallel. 9. If a straight line !>e divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 10. Divide a given... | |
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If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line. 
