It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of the first term. Shorter Course in Algebra - Page 174by George Albert Wentworth - 1887 - 250 pagesFull view - About this book
| George Albert Wentworth - Algebra - 1897 - 386 pages
...quadratic may be made to assume the form of a?x2 ± 2abx = c. To solve such an equation : The first step is to complete the square; that is, to add to each...dividing the second term by twice the square root of (he first term. The second step is to extract the squar* root of each side of the resulting equation.... | |
| George Albert Wentworth - Algebra - 1897 - 382 pages
...only the third term, V, of being a complete square. It will be seen that this third term is the sguare of the quotient obtained from dividing the second term by twice the square root of the first term. 282. Every affected quadratic may be made to assume the form of aV ± 2abx = c. To solve such an equation... | |
| George Albert Wentworth - Algebra - 1897 - 536 pages
...lacks only the third term, b2, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of the Jirst term. 226. Every affected quadratic may be made to assume the form of aV±2eur = c. The first... | |
| Fletcher Durell, Edward Rutledge Robbins - Algebra - 1897 - 482 pages
...quadratic equation the coefficient of ж2 is a square number, we may readily complete the square by dividing the second term by twice the square root of the first term, and adding the square of the quotient thus obtained to both members of the equation. That this process... | |
| George Albert Wentworth - Algebra - 1898 - 440 pages
...the coefficient of x2 is 4, 9, 16, or any other perfect square, we may complete the square by adding to each side the square of the quotient obtained from...second term by twice the square root of the first term. Solve 4 x2 - 23 x = - 30. no The square root of 4z2 is 2x, and 23 x divided by twice 2 x is — •... | |
| George Albert Wentworth - Algebra - 1898 - 434 pages
...the coefficient of x2 is 4, 9, 16, or any other perfect square, we may complete the square by adding to each side the square of the quotient obtained from...second term by twice the square root of the first term. Solve 4 ж2 -23 ж = -30. 23 The square root of 4z2 is 2z, and 23 x divided by twice 2 z is — •... | |
| G. A. Wentworth - 1898 - 422 pages
...may complete the square by adding to each side the square of the quotient obtained from diг-iding the second term by twice the square root of the first term. The square root of 4г2 U 2 x, and 23 x divided by twice 2 x is — • 23 Add the square of — to both... | |
| George Albert Wentworth - 1898 - 436 pages
...we may complete the square by adding to each side the square of the quotient obtained from dividiny the second term by twice the square root of the first term. Solve 4ж2 -23 ж = -30. 23 The square root of 4x2 is 2x, and 23 х divided by twice 2x is — 23 Add... | |
| William James Milne - Algebra - 1901 - 462 pages
...агх? + 2 abx + b!, it is evident that the third term, W, is the square of the quotient obtained by dividing the second term by twice the square root of the first«, EXAMPLES 1. Solve the equation 5 ж2 + 12 x = 9. SOLUTION 5 *2 + 12 x = 9. Multiplying by 6, 25 x2... | |
| Middlesex Alfred Bailey - Algebra - 1902 - 336 pages
...first term is a perfect square. Hence, we multiply the equation by a. iAt2 + abx = ac Its third term is the square of the quotient obtained from dividing...second term by twice the square root of the first. JO Hence, we add to each member (abx -т- 2 Va2ж2)2, or — . Hence, the principle, QED PROPOSITION... | |
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