| 1891 - 718 pages
...angle of a triangle. Explain how the other parts are to be found. 4. Prove the formula which expresses the area of a triangle in terms of two sides and the included angle. 5. One of the equal angles of an isosceles triangle is 75° and the side opposite is 20 feet, find... | |
| University of St. Andrews - 1903 - 762 pages
...between the centres of two adjacent faces, and the diagonal of the cube. C. 14. Find an expression for the area of a triangle in terms of two sides and the included angle. Show that Jc2 sin B (cos B + sin B cot C) is an expression for the area of the triangle ABC. 15. How... | |
| George Sarton - Science - 1922 - 674 pages
...ab* + off* — 2-ab-ag- cos bag, ab ag- sin bag = ad-bg. The first implicit statement of the formula for the area of a triangle in terms of two sides and the sine of the included angle appears to be proposition 26 : « The area of a triangle and the product... | |
| Herbert Ellsworth Slaught - Logarithms - 1914 - 296 pages
...to S=%bc where c is the base and b the altitude. We therefore have a single formula S =1 be sin A 2 for the area of a triangle in terms of two sides and the included angle, whether the latter be acute, right, or obtuse. 41. The law of sines. Since the triangle has three angles... | |
| Ernest Julius Wilczynski - Plane trigonometry - 1914 - 296 pages
...formula reduces to S=%bc where c is the base and b the altitude. We therefore have a single formula for the area of a triangle in terms of two sides and the included angle, whether the latter be acute, right, or obtuse. 41. The law of sines. Since the triangle has three angles... | |
| Sir Thomas Percy Nunn - Algebra - 1914 - 654 pages
...still remains, the second formula becomes area = $bc sin (180° - a). That is to say, we cannot express the area of a triangle in terms of two sides and the included angle without first inquiring whether the angle is acute or obtuse ; the form of the expression being different... | |
| Thomas Percy Nunn, Sir Thomas Percy Nunn - Albegra - 1914 - 762 pages
...still remains, the second formula becomes area = \bc sin (180° - a). That is to say, we cannot express the area of a triangle in terms of two sides and the included angle without first inquiring whether the angle is acute or obtuse ; the form of the expression being different... | |
| Sir Thomas Percy Nunn - Algebra - 1919 - 654 pages
...is obtuse (fig. 71), while the equivalence area = \ca sin /3 2«2 That is to say, we cannot express the area of a triangle in terms of two sides and the included angle without first inquiring whether the angle is acute or obtuse ; the form of the expression being different... | |
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