Every point in the bisector of an angle is equally distant from the sides of the angle ; and every point not in the bisector, but within the angle, is unequally distant from the sides of the angle. Elements of Geometry - Page 72by George Albert Wentworth - 1881 - 250 pagesFull view - About this book
| Teachers - 1901 - 258 pages
...principal in three years at 4 per cent. will amount to $448. Take either 1 or 2. 1. Prove that any **point in the bisector of an angle is equally distant from the sides of the angle.** 2. Prove that the line dividing two sides of a triangle proportionally is parallel to the third side.... | |
| Alan Sanders - Geometry, Modern - 1901 - 260 pages
...of the rectangle is less than that of the rhomboid. PROPOSITION XXXVIII. THEOREM 230. Any point on **the bisector of an angle is equally distant from the sides of the angle; and** any point not on the bisector is unequally distant from the sides. BB Let ABC be any angle, BD its... | |
| American School (Chicago, Ill.) - Engineering - 1903 - 390 pages
...and ABE, is greater than angle A. Therefore angle BDC is greater than angle A. THEOREM XXV. 89. Any **point in the bisector of an angle is equally distant from the sides of the angle.** Let BD be the bisector of an angle, ABC, and let P be any point in B D. To prove that P is equally... | |
| Alan Sanders - Geometry - 1903 - 396 pages
...less than that of the rhomboid. SANDERS' GEOM. — 5 PROPOSITION XXXVIII. THEOREM 230. Any point on **the bisector of an angle is equally distant from the sides of the angle; and** any point not on the bisector is unequally distant from the sides. Let ABC be any angle, BD its bisector,... | |
| Alan Sanders - Geometry - 1903 - 392 pages
...of the rectangle is less than that of the rhomboid. PROPOSITION XXXVIII. THEOREM 230. Any point on **the bisector of an angle is equally distant from the sides of** tlie angle; and any point not on the bisector is unequally distant from the sides. BB Let ASC be any... | |
| William Chauvenet - 1905 - 336 pages
...point not on the perpendicular is unequally distant from the extremities of the line. PROPOSITION XIX. **Every point in the bisector of an angle is equally...of the angle ; and every point not in the bisector** is unequally distant from the sides of the angle ; that is, the bisector of an angle is the locus of... | |
| George Clinton Shutts - 1905 - 260 pages
...points without the _L from the extremities. § 88. 4. What is the required locus ? Ex. 68. Prove that **every point in the bisector of an angle is equally distant from the sides of the angle.** Suggestion: OM and 0 N are _L to AB and AC respectively. § 131. Prove OM equal to O N. PROPOSITION... | |
| Edward Rutledge Robbins - Geometry, Plane - 1906 - 268 pages
...point to two lines are equal, the point is said to be equally distant from the lines. 79. THEOREM. **Every point in the bisector of an angle is equally distant from the sides of the angle.** Given: Z ACE; bisector CQ; point P in C'Q; distances PB and To Prove : PH = Pii. Proof: A PBC and PDC... | |
| International Correspondence Schools - Building - 1906 - 634 pages
...CD, that is, OC, which meets the bisectors AO and BO in O, is the bisector of the angle C. 101. Any **point in the bisector of an angle is equally distant from the sides of the angle.** For it has just been shown that, in Fig. 69, OF= O E. 102. The perpendiculars erected at the middle... | |
| Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...point to two lines are equal, the point is said to be equally distant from the lines. 79. THEOREM. **Every point in the bisector of an angle is equally distant from the sides of the angle.** Given : Z ACE; bisector CQ; point P in CQ; distances PB and PD. To Prove : PB = PD. Proof : A PBC and... | |
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