 | Henry Lewis (M.A.) - Measurement - 1875 - 104 pages
...be determined from its three sides by the following rule: — From half the sum of the three sides, subtract each side separately; then multiply the half sum and the three remainders together, and the square root of the last product will be the area of the triangle. For practical purposes this rule... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...find the area of a triangle when three sides are given. RULE. — From half the sum of the three sides subtract each side separately. Then multiply the half sum and the three remainders continually together, and the square root of the product will he the area. EXAMPLES. 1. Required the... | |
 | Joseph Ray - Arithmetic - 1877 - 402 pages
...Rule. — 1. From half the sum of the three sides take each side separately. 2. Multiply the half-sum and the three remainders together, and extract the square root of the product. '. The base of a triangle is 15 ft. and its altitude 12 ft. : what is its area ? 90 sq. ft. f. One side of... | |
 | Joseph Ray - Arithmetic - 1877 - 350 pages
...Bule. — 1. From half the sum of the three sides take each side separately. 2. Multiply the half-sum and the three remainders together, and extract the square root of the product. 1. The base of a triangle is 15 ft. and its altitude 12 ft. : what is its area ? 90 sq. ft. 2. One... | |
 | Popular encyclopedia - 1877 - 526 pages
...lengths of the sides are known; from half the sum of the three sides subtract each side separately; multiply the half sum and the three remainders together, and extract the square-root of the product. Area of any parallelogram = any side multiplied by the perpendicular distance... | |
 | Alfred Hiley - 1879 - 228 pages
...are equal to two right angles, then its area will be found thus : — Add together the four sides, and take half their sum. From this half sum subtract each side separately. Multiply these four remainders together, and the square root of the product is the area of the trapezium.... | |
 | Thomas Liddell Ainsley - 1880 - 866 pages
...be determined from its three sides by the following EULE LXV. From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together, and the square root of the latí product mill be the area of the triangle. For practical purposes this... | |
 | Joseph Ficklin - Arithmetic - 1881 - 406 pages
...360000. -Y/360000 = 600 ; hence the area is 600 sq. ft. RDLE. — From the half sum of the three sides, subtract each side separately ; then multiply the...the square root of the product. The result will be ihe area. 6. What is the area of a triangle, whose sides are 25, 36, and 49 inches ? 7. How many acres... | |
 | Joseph Ficklin - Arithmetic - 1881 - 412 pages
...36COOO. -y/360000 = 600 ; hence the area is 600 sq. ft. RULE. — From the half sum of the three sides, subtract each side separately; then multiply the half...together, and extract the square root of the product. Tlie result will be the area. 6. What is the area of a triangle, whose sides are 25, 36, and 49 inches... | |
 | Henry H. Hutton - Measurement - 1882 - 178 pages
...any triangle to find its area. Rule II. From half the sum of the three sides subtract the three sides separately; then multiply the half sum and the three...together, and extract the square root of the product ; or,— A= fm (ma) (in-b) (mc). EXERCISE. H. 1. Find the area of a triangle whose sides are respectively... | |
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Multiply the half sum and the three remainders together, and extract the square root of the product. EXAMPLES. 1. What is the area of a triangle whose sides are respectively 30, 40, and 50 feet ? 30 + 40 + 50 = 120. 
