 | Samuel Read Hall - Arithmetic - 1832 - 294 pages
...the last quotient, and cube the last quotient, and add these products together and take the amount from the dividend. and to the remainder bring down the next period. Proceed as before, till the whole is finished. 1. What is the cube root of 15625? 15625(25 root The... | |
 | Charles Davies - Arithmetic - 1833 - 284 pages
...divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
 | Daniel Adams - Arithmetic - 1833 - 268 pages
...the cube of this quotient figure, and call their amount the subtrahend. VII. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on, till the whole is finished. Note 1. If it happens that the... | |
 | Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...and add these three results together for a subtrahend. 5. Subtract the subtrahend from the dividend. To the remainder bring down the next period, for a new dividend, and proceed as before. If it happens in any case, that the divisor is not contained in the dividend,... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...in the root ; add these three last found numbers together, and subtract this sum from the dividend ; to the remainder bring down the next period for a new dividend, and proceed as before. EXAMPLE. — Required the cube root of 44419494". 444194947(763 343 7 x 7 x... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...Lastly — Multiply the divisor thus completed, by the figure last placed in the root, and subtract the product from the dividend; and to the remainder bring down the next period for a new dividend. Thus proceed, till the whole root is extracted. Observe, that, when the divisor is not contained in... | |
 | Charles Davies - Algebra - 1835 - 378 pages
...divisor. IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root already found, for a new divisor, and continue the operation as before, until... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...adding thereto SO times the product of the last figure of the root into the rest. Multiply, subtract, and to the remainder bring down the next period for a new resolvend : add together the last complete divisor, the number that completed it, and twice the square... | |
 | Benjamin Snowden - 1835 - 108 pages
...greater than the dividend, put a less figure than the last to the root, and alter the work. 8. — To the remainder bring down the next period for a new dividend, with which proceed as with the first dividend, until all the periods are brought down. Prove the work... | |
 | Lyman Cobb - Arithmetic - 1836 - 228 pages
...write the cube of this quotient figure, and call the amount the subtrahend. 1. Substract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on, till the whole is finished. NOTE. — If the divisor can... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
