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" A line parallel to one side of a triangle divides the other two sides proportionally. "
Schultze and Sevenoak's Plane and Solid Geometry - Page 160
by Arthur Schultze, Frank Louis Sevenoak - 1913 - 457 pages
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Mathematics for Shop and Drawing Students

Harry Morton Keal, Clarence J. Leonard - Mathematics - 1921 - 238 pages
...proportion the product cf the extremes equals the product of the means: ie, if then a : b ::c :d, ad=bc. 2. A line parallel to one side of a triangle divides the other two sides proportionally. 3. The medians of a triangle meet in a point two-thirds of the distance from the vertex to the mid-point...
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Junior High School Mathematics, Book 3

John Charles Stone - Mathematics - 1921 - 272 pages
...is 80*yd, EC 20 yd, and DC 15 yd., what is the width of the stream ? 8. It is known in geometry that a line parallel to one side of a triangle divides the other two sides into four proportional parts. That is, if DE is parallel to AB, -^ =~ DA EB (1) If J_D=6 in., DC=13...
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General Mathematics, Book 2

Raleigh Schorling, William David Reeve - Mathematics - 1922 - 476 pages
...if d is trebled? 12. How does the formula Id* = k illustrate functional relationship ? 353. Theorem. A line parallel to one side of a triangle divides the other two sides proportionally. C FIG. 352 Given the triangle ABC, with DE parallel to AB. CD _ CE I)A~lSB To prove that STATEMENTS...
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Drill Book in Plane Geometry

Robert Remington Goff - 1922 - 136 pages
...respectively to three terms of another proportion, what can be said of the remaining terms? 245. A straight line parallel to one side of a triangle divides the other two sides proportionally. 246. Arrange the proportion of 245 by composition. *247. PROBLEM : Find the fourth proportional to...
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Schultze and Sevenoak's Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 484 pages
...COR. A central angle is measured by its intercepted arc. PLANE GEOMETRY PROPOSITION II. THEOREM 475. A line parallel to one side of a triangle divides the other two sides proportionally. 8 Given in A ABC, DE parallel to BC. To prove AD : DB = AE : EC. Proof. CASE I. AD and DB are commensurable....
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Junior High School Mathematics: 1st-3d Book, Book 3, Part 2

Edson Homer Taylor, Fiske Allen - Mathematics - 1923 - 104 pages
..., CK my m and .£^5 = — - = -. KB ny n ™, AH CK . . . Then 77.=, = ^^. Axiom o 190. Corollary. A line parallel to one side of a triangle divides the other two sides so that one side is to either of its segments as the other side is to the corresponding segment. Prove...
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Essentials of Plane Geometry

David Eugene Smith - Geometry, Plane - 1923 - 314 pages
...CASES SUPPLEMENT 313. Sides of a Triangle. In § 201 it was proved for the commensurable case that a line parallel to one side of a triangle divides the other sides proportionally. We shall now prove the theorem for the incommensurable case. Divide CD into any...
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Book Three

Joseph Clifton Brown, Albert Clayton Eldredge - Arithmetic - 1924 - 346 pages
...be used in finding BO? Find BO when AB is 5 ft. and BE is 3 ft. 15. After reading in a geometry that a line parallel to one side of a triangle divides the other two sides proportionally, Fred and Henry worked out the following method for finding the distance across a lake. They measured...
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Plane Geometry: (Revised)

Claude Irwin Palmer, Daniel Pomeroy Taylor, Eva Crane Farnum - Geometry, Modern - 1924 - 360 pages
...facts shown in this experiment are stated and proved in the theorem of § 360. 360. Theorem. A straight line parallel to one side of a triangle divides the other two sides proportionally. Given AABC having DE II AC. ftl T To prove that — = -, where m = AD, n = DB, r = CE, and = EB. ns Proof....
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Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - Geometry - 1925 - 504 pages
...continued ratio of 2 : 3 : 4. Find the segments. I PROPORTIONAL LINES PROPOSITION XIII. THEOREM1 292. A line parallel to one side of a triangle divides the other two sides into segments that are proportional. B c Given in AABC, DE parallel to BC. To prove AD:DB = AE: EC....
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