 | Horatio Nelson Robinson - Algebra - 1874 - 340 pages
...and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 468 pages
...for a trial figure in the root. I\ . Annex the trial figure of the root to the trial divisor for a complete divisor ; multiply the complete divisor by...the product from the dividend, and to the remainder briny down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 496 pages
...for a trial figure in the root. I\ . Annex the trial figure of the root to the trial divisor for a, complete divisor ; multiply the complete divisor by...the product from, the dividend, and to the remainder briny down the next period for a new dividend. V. Multiply the last figure of the last complete divisor... | |
 | Horatio Nelson Robinson - Algebra - 1875 - 338 pages
...root and at the right of the divisor. IV. Miiltiply the divisor thus completed by the last, figure of the root ; subtract the product from the dividend,...bring down the next period for a new dividend. V. Double the right-hand figure of the last complete divisor for a new divisor, and continue tiie operation... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...the right of the divisor. IV. Multiply the divisor thus obtained by the digit of the root last found: subtract the product from the dividend, and to the...bring down the next period for a new dividend. V. Double the part of the root already found, for a new divisor, and proceed as before ; and so on, through... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...result will be the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract Hie product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the rool,t the last term in column II, and the complete divisor... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial figure of the root, subtract the product from the dividend, and to the remainder annex the -following period for a new dividend. V. Proceed as before, continuing the operation till... | |
 | Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1875 - 406 pages
...trial figure in the root. IV. Add the trial figure of the root to the trial divisor for a cojnplete divisor ; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new... | |
 | Thomas Henderson - 1876 - 114 pages
...30, and also the square of the last figure. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder bring down the next period, if any, or add three cyphers, for a new dividend. To the last complete divisor add the two numbers... | |
 | Edward Brooks - Arithmetic - 1876 - 588 pages
...root ; their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
