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" This sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. "
New Complete Arithmetic on the Inductive Method: With Parallel Mental and ... - Page 265
by James William Nicholson - 1885 - 326 pages
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The Elements of Mechanical Engineering, Volume 1

Electrical engineering - 1897 - 672 pages
...the number in the first column, multiply the sum by the second figure of the root, and add the result to the trial divisor to form the complete divisor....divisor by the second figure of the root, subtract the result from the dividend in the third column, and annex the third period to the remainder for a ne'M...
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An Advanced Arithmetic for High Schools, Normal Schools, and Academies

George Albert Wentworth - Arithmetic - 1898 - 424 pages
...considered as tens by the second figure, and also the square of the second figure. This sum will be the complete divisor. Multiply the complete divisor...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result...
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An Advanced Arithmetic for High Schools, Normal Schools, and Academies

George Albert Wentworth - Arithmetic - 1898 - 424 pages
...considered as tens by the second figure, and also the square of the second figure. This sum will be the complete divisor. Multiply the complete divisor...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result...
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An Advanced Arithmetic

George Albert Wentworth - 1898 - 424 pages
...considered as tens by the second figure, and also the square of the second figure. This sum will be the complete divisor. Multiply the complete divisor...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result...
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The Werner Arithmetic: Oral and Written, Book 3

Frank H. Hall - Arithmetic - 1898 - 326 pages
...the quotient as the second figure of the root, and also as a part of the divisor. Multiply the entire divisor by the second figure of the root, subtract the product from the dividend and proceed as before. NOTE.—If, in applying the foregoing rule, a dividend is found that will not con....
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The Werner Arithmetic: Oral and Written. Book III--parts I and II, Volume 3

Frank H. Hall - Arithmetic - 1898 - 298 pages
...the quotient as the second figure of the root, and also as a part of the divisor. Multiply the entire divisor by the second figure of the root, subtract the product from the dividend and proceed as before. NOTE.— If, in applying the foregoing rule, a dividend is found that will not contain...
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The Werner Arithmetic: Oral and Written, Book 3

Frank H. Hall - Education - 1898 - 296 pages
...the quotient as the second figure of the root, and also as a part of the divisor. Multiply the entire divisor by the second figure of the root, subtract the product from the dividend and proceed as before. NOTE.— If, in applying the foregoing rule, a dividend is found that will not contain...
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A Practical Arithmetic

George Albert Wentworth - Arithmetic - 1899 - 404 pages
...considered as tens by the second figure, and also the square of the second figure. This sum will be the complete divisor. Multiply the complete divisor...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been annexed. The result...
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For 6th-8th grade

George Edward Atwood - Arithmetic - 1899 - 392 pages
...quotient to the root and also to the divisor. Multiply the completed divisor by the last figure in the root, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in the same manner until all the periods have been used. NOTE 1. If the...
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A Complete Arithmetic ...

Frank H. Hall - Arithmetic - 1899 - 456 pages
...the quotient as the second figure of the root, and also as a part of the divisor. Multiply the entire divisor by the second figure of the root, subtract the product from the dividend, and proceed as before. PROBLEMS. Find the approximate square root (true to tenths) : (1) 875. (2) 1526....
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