 | Aaron Schuyler - Measurement - 1864 - 506 pages
...6.3589. Since a > p and a < b, there are two solutions. Since the side opposite the given angle is to th& side opposite the required angle as the sine of the...given angle is to the sine of the required angle, we have the proportion, , . . ,, „ b sin A a : b : : sin A : sin B. .-. sin B = a log sin B = log... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...(7, and c. From Formula (13), we have, a : b : : sin A : sin B ; that is, the uide opposite the ginen angle, is to the side opposite the required angle, as the sine of the given angle is "' the sine of the required angle. Whence, by the application of logarithms, (ac) log a + log I + log... | |
 | Aaron Schuyler - Measurement - 1875 - 284 pages
...9.70439 log p = 0.80338 . • . p = 6.Ü589. Since a > p and o < b, there are two solutions. Since the side opposite the given angle is to the side opposite...given angle is to the sine of the required angle, we have the proportion, _ b sin A a : b :: sin A : s1n B, .'. s1n ß = 1t log sin Б = log b + log... | |
 | Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...continued application of formula (13). Examples. From formula (13), we have 0:6:: sin A : sin B ; that is, the side opposite the given angle, is to the side opposite the required angle, <1s the sine of the given angle is to the sine of the required angle. Whence, by the application of... | |
 | Elias Loomis - Trigonometry - 1886 - 436 pages
...side and the remaining angles. One of the required angles is found by Theorem I. The proportion is, The side opposite the given angle is to the side opposite...given angle is to the sine of the required angle. The third angle is found by subtracting the sum of the other two from 180° ; and the third side is... | |
 | William Kent - Engineering - 1895 - 1234 pages
...(îiveii two sides and an angle opposite one of them, to find tht third side and the remaining angles. The side opposite the given angle is to the side opposite the required angle as the sine of the given an^le is tu the nine of the required angle. The third angle is found by subtracting the sum of tile... | |
 | William Chauvenet - Geometry - 1896 - 274 pages
...tables. 132. CASE II. Given two sides and an angle opposite one of them, or a, b and A. To ßnd В. То find the angle opposite the other given side, we apply...with the present data, we have a : b = sin A : sin Б whence sin В = - (249^ Kg. 19. Tu find С. We have 0= 180° - (A -i- B) To find c. Having found... | |
 | William Kent - Engineering - 1907 - 1206 pages
...Given two sides and an augle opposite one of them, to find the third side and the remaining angles. The side opposite the given angle is to the side opposite...given angle is to the sine of the required angle. The third angle is found by subtracting the sum of the other two from 180", and the third side is found... | |
 | William Kent - Engineering - 1902 - 1204 pages
...Given two sides and an angle opposite one of them, to find the tliird side and the remaining angles. The side opposite the given angle is to the side opposite...required angle as the sine of the given angle is to the Bine of the required angle. The third angle is found by subtracting the sum of the other two from 180°,... | |
 | William Kent - Engineering - 1902 - 1224 pages
...Given two sides and an angle opposite one of them, to find the third side and the remaining angles. The side opposite the given angle is to the side opposite...required angle as the sine of the given angle is to the Bine of the required angle. The third angle is found by subtracting the sum of the other two from 180»,... | |
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The side opposite the given angle is to the side opposite the required angle as the sine of the given angle is to the Bine of the required angle. 
