| James Bates Thomson - Arithmetic - 1847 - 426 pages
...&c., is given, the price of one is found by simply removing tlie decimal point in the given cost or **dividend, as many places to the left as there are ciphers in the divisor.** (Art. 331.) 28. Bought 1000 bricks for $7.20 : what is that apiece ? 29. If 1000 feet of hemlock boards... | |
| William Vogdes - Arithmetic - 1847 - 324 pages
...quotient carried on to any degree of exactness. 4. To divide by 10, 100, 1000 or the like, move the point **as many places to the left as there are ciphers in the divisor.** The quotient figure is always of the same value with that figure of the dividend, under which the units... | |
| James Bates Thomson - Arithmetic - 1848 - 434 pages
...&c., is given, the price of one is found by simply removing the decimal point in the given cost or **dividend, as many places to the left as there are ciphers in the divisor.** (Art. 331.) 28. Bought 1000 bricks for $7.20 : what is that apiece? 29. If 1000 feet of hemlock boards... | |
| Rufus Putnam - Arithmetic - 1849 - 276 pages
...cancel the 15.203 0, and divide by 2. See margin. RULE. When the divisor IMS naughts on the right, **remove the decimal point in the dividend as many places to the left as there are** naughts on the right of the divisor; cancel the naughts, and divide by the remaining figure or figures.... | |
| Rufus Putnam - Arithmetic - 1849 - 402 pages
...since it makes units tenths, tens units, &c. Hence the following RULE. To DIVIDE BY 10, 100, 1000, &c. **Remove the decimal point in the dividend as many places to the left as there** naughts at the right of the divisor. EXAMPLES. 1. Divide 304617 by 10. Am. 30461.7. By 100; by 1000.... | |
| George Roberts Perkins - Arithmetic - 1849 - 346 pages
...•57". We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point **as many places to the left as there are ciphers in the divisor** : when there are not so many figures at the left of the decimal point, we may prefix ciphers. 10 100... | |
| George Roberts Perkins - Arithmetic - 1850 - 364 pages
...2-223+. 57. We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point **as many places to the left as there are ciphers in the divisor** ; when there are not so many figures at the left of the decimal point, we may prefix ciphers. 1-212.... | |
| George Roberts Perkins - Arithmetic - 1851 - 356 pages
...2-223+. Sf. We may, obviously, divide any decimal by 10, 100, 1000, &c., by removing the decimal point **as many places to the left as there are ciphers in the divisor;** when there are not so many figures at the left of the decimal point, we may prefix ciphers. 10 100... | |
| Calvin Tracy - 1851 - 214 pages
...(See 4th sum.) § 90, — To divide a decimal by 10, 100, 1000, &c. RULE. Remove the decimal point **as many places to the left as there are ciphers in the divisor.** 1. Divide 30515.50 by 100. Ans. 305.1550. 2. Divide 36.5 by 10. Ans. 3.65. 3. Divide 36.10 by 100.... | |
| John Hunter - Arithmetic - 1852 - 184 pages
...annexed, is used as a divisor, the quotient may be represented by merely shifting the decimal point of **the dividend as many places to the left as there are ciphers in the divisor.** Thus, * 860-=- 100 = 860-0 -r- 100 = 8'6; 45 -4- 1000 = 45-0 -4- 1000 = -045; 23-47 -h 10000 = -002347.... | |
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