 The area of a regular inscribed hexagon is a mean proportional between the areas of the inscribed and circumscribed equilateral triangles. Ex.  Plane and Solid Geometry - Page 243by Edward Rutledge Robbins - 1907 - 412 pagesFull view - About this book
 | William Betz, Harrison Emmett Webb, Percey Franklyn Smith - Geometry, Plane - 1912 - 356 pages
...area of the circumscribed equilateral triangle. 9. The area of the regular inscribed hexagon is the mean proportional between the areas of the inscribed and the circumscribed equilateral triangles. 10. In Ex. 6 compare the area of the given hexagon with that of any one of the figures pointed out.... | |
 | William Weller Strader, Lawrence D. Rhoads - Geometry, Plane - 1927 - 434 pages
...GH. Prove OC : OB = OH : OG. 25. Show that the area of a regular hexagon inscribed in a circle is the mean proportional between the areas of the inscribed and the circumscribed equilateral triangles. 26. One base of a trapezoid is 10 in., the altitude is 4 in. and the area is 32 sq. in. Find the length... | |
 | Webster Wells - Geometry - 1887 - 144 pages
...A = 3 R2 л/3. But, f Д2л/ЗхЗ.КЧ/3==^.К1 = (| #V3)2. .-. the area of the regular inscribed hexagon is a mean proportional between the areas of the inscribed and circumscribed equilateral A. 9. From proof of Prop. VIII. , Z OEM = Z BOM = 36°. Then in the О described... | |
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