 | Charles Davies - Arithmetic - 1846 - 362 pages
...it is less place the greater there. IV. Then multiply the second and third terms together and Ans. divide the product by the first term: the quotient will be the fourth term or answer sought, and will be of the same denomination as the third term. Ex. 3. If 48... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. Multiply the second and third terms together, and divide the product by the first; the quotient will be the answer to the question in the same denomination as the third term. 3. If either... | |
 | Arithmetic - 1847 - 292 pages
...denomination; and reduce the middle number, or term, into the lowest denomination mentioned; then (7) multiply the second and third terms together, and divide the product by the first; the quotient will be (°) the answer, or fourth term sought; and always will be (a) of the same denomination... | |
 | Isaiah Steen - 1848 - 316 pages
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, multiply the second and third terms together, and divide the product by the first term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination as the last... | |
 | William B. Young - Ready-reckoners - 1848 - 320 pages
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen multiply the second and third Terms together, and divide the product by the first Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term was reduced,... | |
 | rev. Frederick Calder - 1848 - 190 pages
...so : and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then multiply the second and third terms together, and divide the product by the first: the quotient will be the answer or fourth term, expressed in the same denomination as that in which... | |
 | Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...term, place the least of the two remaining numbers fqr the second term, and the greater for the first term ; then multiply' the second and third terms together, and divide the -product by the first term, and the quotient will be the answer in the same name "of the third term EXAMPLES. 1. If 6 yards cost... | |
 | J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...of the two remaining numbers for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. NOTE. — If the first... | |
 | George Roberts Perkins - Arithmetic - 1849 - 346 pages
...Having written the three terms of the proportion, or, as usually expressed, having stated the question, then multiply the second and third terms together, and divide the product L,j the first term. NOTE. — Since there is a ratio between the first and second terms, they must... | |
 | George Roberts Perkins - Arithmetic - 1850 - 364 pages
...Having written the three terms of the proportion, or, as usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by the first term. NOTE. — Since there is a ratio between the firsthand second terms, they must be reduced to the same... | |
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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 
