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" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
Mathematical Dictionary and Cyclopedia of Mathematical Science Comprising ... - Page 80
by Charles Davies, William Guy Peck - 1859 - 592 pages
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Elementary and practical Arithmetic on the inductive system, by analysis and ...

Charles WATERHOUSE - Arithmetic - 1844 - 228 pages
...term, write the less of the two remaining numbers for the second term, and the other for the first Multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer. If the first and second terras be compound numbers, reduce those...
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Arithmetic Designed for Academies and Schools: With Answers

Charles Davies - Arithmetic - 1844 - 358 pages
...the remaining numbers in the first place, but when it is less place the greater there. RULE OF THREE. divide the product by the first term: the quotient will be the fourth term or answer sought, and will be of the same denomination as the third term. Ex. 3. If 48...
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A system of practical arithmetic

William Lane (of Worthing.) - 1845 - 138 pages
...proportion, if necessary, to the same name, and reduce the third term to the lowest denomination it contains. Then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer to the question, in the same denomination that the third term was...
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The Teachers' Assistant, Or, A System of Practical Arithmetic: Wherein the ...

Arithmetic - 1845 - 196 pages
...VULGAR FRACTIONS. RULE. Prepare the given terms, if necessary, and state (hem as in whole numbers ; multiply the second and third terms together, and divide the product by the first Or, Invert the dividing term, and multiply the three terms together, as in Multiplication. EXAMPLES....
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Watson's Tutor's assistant; or, Complete school arithmetic

William Watson (of Beverley.) - 1845 - 188 pages
...Bring the first and third into one name, and the second into the lowest name mentioned in it. 3. — Multiply the second and third terms together and divide the product by the first, the quotient will be the answer to the question in the same name the second term was brought into....
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The Practical Miner's Guide: Comprising a Set of Trigonometrical Tables ...

John Budge - 1845 - 248 pages
...SHROUD-LAID* ROPE. RULE — State the question as in direct proportion, square the first and third terms, multiply the second and third terms together, and divide the product by the first. EXAMPLE. How many standard yarns, or threads, are there in a 14-inch capstan rope ? in. yarns. in....
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System of Practical Arithmetic

Arithmetic - 1845 - 210 pages
...term consist of several ^nominations, reduce it to its lowest denomination : then, multiply the 'cond and third terms together, and divide the product by the first term; le quotient will be the fourth term, or answer, in the same denomination ï the second, or that to...
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The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - Arithmetic - 1846 - 370 pages
...least of the remaining numbers in the first place, but when it is less place the greater there. IV. Then multiply the second and third terms together,...^product by the first term : the quotient will be the fourth term or answer sought, and will be of the same denomination as the third term. EXAMPLES. 1....
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North American Arithmetic: Part Second and Part Third, Part 2

Frederick Emerson - Arithmetic - 1846 - 266 pages
...than the third, make the less of the two remaining terms the second term, and the greater the first. Multiply the second, and third terms together, and...product by the first term: the quotient will be the fourth term, or answer. If there are different denominations in the first two terms, they must both...
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An Elementary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - Arithmetic - 1846 - 266 pages
...Having written the three terms of the proportion, or, at usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by <A« first term. :!:NoTE. — Since there is a ratio between the first and cond terms, they must be...
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