 | Robert Patterson - Arithmetic - 1819 - 174 pages
...we have the equation ad = be, and this divided by a, will give d = —. In words — multiply the a second and third terms together, and divide the product by the first, and the quotient will be the fourth, or term required. II. IN ALLIGATION ALTERNATE. Let a, A, = the... | |
 | Jacob Willetts - Arithmetic - 1822 - 200 pages
...DIRECT PROPORTION. RULE. Prepare the given terms, if necessary, and state them as ia whole numbers : multiply the second and third terms together, and divide the product by the first : Or, Invert the first term and multiply the three together, as in Multiplication. EXAMPLES. i . If... | |
 | Zachariah Jess - Arithmetic - 1824 - 224 pages
...dols. ' A " 5 ' 3 : 6 :: 9 : 1 8 more requiring more I 20 : 40 :: 3 : 10 less requiring less RULE. Multiply the second and third terms together, and divide the product by the first ; the quotient will be the fourth term, or answer ; in the same name with the second. PROOF. Invert... | |
 | Stephen Pike - Arithmetic - 1824 - 212 pages
...THREE, IN VULGAR FRACTIONS. Prepare the given terms, if necessary, and state them as in whole numbers ; multiply the second and third terms together, and divide the product by the first. Or, Invert the dividing term, and multiply the three terms together, as in Multiplication. EXAMPLES.... | |
 | Thomas Tucker Smiley - Arithmetic - 1825 - 224 pages
...second terms to the same denomination, and to the lowest denomination mentioned in either oi them. 3. Multiply the second and third terms together, and divide the product by the first term; the result will be-tbe fourth term OF answer in the same denomination to which the third term was reduced.... | |
 | Samuel Temple - Arithmetic - 1825 - 118 pages
...mentioned. Having properly stated the question, multiply the second and third terms into each other, and divide the product by the first term ; the quotient will be the answer, or number, sought. JVo/e 3. The answer always come: in the same denomination with the middle... | |
 | Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 214 pages
...kind, the first term ; and that which is of the same name or kind with the answer, the second term. 2. Multiply the second and third terms together, and divide the product by the first term, and the quotient will be the fourth term, or answer. The notes under the general rule are applicable... | |
 | Poplar House Academy - 1826 - 100 pages
...when necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then, multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ;... | |
 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...the same kind, the first term, and that which is of the same kind as the answer, the second term. 2.f Multiply the second and third terms together, and divide the product by the first, the quotient will be the answer. EXAMPLE. — If 8lb. of sugar cost $1.00, what will 401b-. of sugar... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination... | |
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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 
