 | Ebenezer Bailey - Algebra - 1844 - 266 pages
...Multiply the whole divisor by this term, and subtract the product from the dividend. Divide the ßrst term of the remainder by the first term of the divisor,...for the second term of the quotient. Multiply the whole divisor by this second term, and subtract the product from the remainder. Continue this series... | |
 | William Scott - Algebra - 1844 - 568 pages
...term of the quotient. Multiply the divisor by this term, and subtract the product from the quotient. . Divide the first term of the remainder by the first term of the divisor; the result is the second term of the quotient. Multiply the divisor by the second term of the quotient,... | |
 | James Bates Thomson - Algebra - 1844 - 272 pages
...term, for the first term of the required root : III. Subtract the power from the given quantity, and divide the first term of the remainder by the first term of the root in volved to the next inferior power and multiplied by the index of the given power ;* the quotient... | |
 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...first term of the quotient, and subtract the product from the dividend, and oring down the remainder. Divide the first term of the remainder by the first term of the divisor, and the quotient will be the second term of the quotient ; multiply the divisor by the second term... | |
 | Samuel Alsop - Algebra - 1846 - 300 pages
...thus determined, and subtract the product from the dividend, arranging the terms as above directed. Divide the first term of the remainder by the first term of the divisor, and so proceed until the operation is accomplished. EXAMPLES. Ex. 1. a — x) a3 — 2 ax + x3 (a —... | |
 | Harvey Goodwin - Mathematics - 1846 - 500 pages
...term of the dividend by the first term of the divisor gives the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend ; bring down as many more of the terms of the dividend as may be required, and repeat the process until... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...dividend by the first term of the divisor, the result will be thefirst term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by t he first term of the divisor, the result will be the... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...dividend by the first term of the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by the first term of the divisor, the result will be the... | |
 | Jeremiah Day - Algebra - 1847 - 358 pages
...term, for the first term of the required root : • Subtract the power from the given quantity, and divide the first term of the remainder, by the first term of the root involved to the next inferior power, and multiplied by the index of the given power ;f the quotient... | |
 | George Roberts Perkins - Algebra - 1847 - 432 pages
...the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Tfien divide the first term of the remainder by thefirst term of the divisor, which gives the second... | |
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... the first term of the quotient ; multiply the• divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor... 
