| Thomas Lund - Geometry - 1854 - 192 pages
...angles as the polygon has sides. But the angles at 0 are equal to four right angles (30 Cor.); .'. all **the angles of the polygon are equal to twice as many right angles as the** polygon has sides, diminished by four right angles. COR. 1 . Hence, all the angles of a pentagon =... | |
| Popular educator - 1854
...divide it into three equal parts. *"'t 3Fig. .42. No. 3. interior angles together with four right angles **are equal to twice as many right angles as the figure has sides.** Therefore all the interior angles together with all the exterior angles are equal (Ax. 1) to all the... | |
| E. W. Beans - Surveying - 1854 - 114 pages
...taken. If the entire survey has been made as above directed, the sum of all the internal angles will be **equal to twice as many right angles as the figure has sides,** diminished by four right angles. If this sum, as in practice will be likely to be the case, should... | |
| Charles Davies - Geometry - 1854 - 436 pages
...triangles in the figure ; that is, as many times as there are sides, less two. But this product is **equal to twice as many right angles as the figure has sides,** less four right angles. Cor. 1. The sum of the interior angles in a quadrilateral is equal to two right... | |
| Euclides - 1855
...angles, and there are as many triangles in the figure as it has sides, all the angles of these triangles **are equal to twice as many right angles as the figure has sides.** But all the angles of these triangles are equal to the interior angles of the figure, viz. ABС, BСD,... | |
| William Mitchell Gillespie - Surveying - 1855 - 436 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is **equal to twice as many right angles, as the figure has sides** less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| Henry James Castle - Surveying - 1856 - 185 pages
...angles are the exterior angles of an irregular polygon ; and as the sum of all the interior angles **are equal to twice as many right angles, as the figure has sides, wanting four** ; and as the sum of all the exterior, together with all the interior angles, are equal to four times... | |
| Āryabhaṭa - 1878
...been proved by the foregoing corollary, that all the interior angles together with four right angles **are equal to twice as many right angles as the figure has** sidesTherefore all the interior angles together with all the exterior angles are equal (Ax. 1) to all... | |
| Surveying - 1878 - 534 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is **equal to twice as many right angles, as the figure has sides** less two; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| Charles Mansford - 1879 - 112 pages
...of the other angles that the interior angles of any rectilineal figure together with 4 right angles **are equal to twice as many right angles as the figure has sides.** (32.) 113. If two angles have their containing sides respectively parallel to one another the lines... | |
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