| Arthur Morley, William Inchley - Mechanical engineering - 1911 - 400 pages
...distance from that side to the opposite side. In Fig. i area = ax d. Trapezoid. — Multiply one-half the sum of the parallel sides by the perpendicular distance between them, or area= X d (Fig- 0divide the product by 4 ; or, if d = diameter, then area = — , where 4 ir = 3-1416.... | |
| Jay Brownlee Davidson - Agricultural engineering - 1913 - 570 pages
...18.) This is a four-sided figure with two sides parallel. The area is equal to the product of one-half the sum of the parallel sides by the perpendicular distance between them. a+b Flg' 18' Area Xh. Fig. 19. where a and b are the two parallel sides, and h the perpendicular distance... | |
| Clement Mackrow - Naval architecture - 1916 - 766 pages
...perpendicular height, then A = ab. 2. To find the area of a trapezoid. (Fig. 55.) RULE. — Multiply the sum of the parallel sides by the perpendicular distance between them; half the product will be the area. Thus, if A = the area, b and a = the parallel sides, and c = the... | |
| William Miller Barr - Engineering - 1918 - 650 pages
...Area of a Trapezoid, or a Quadrangle, Two of Whose Opposite Sides Are Parallel. — Rule: Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. To Find the Area of a Regular Polygon. — Rule: Multiply half... | |
| Wilfred Welday Scott - Analytical chemistry - 1922 - 964 pages
...multiply the length of one side by the vertical distance to. the parallel side. Trapezoid. Area = multiply half the sum of the parallel sides by the perpendicular distance between the two. Circle. Area = 0.78.54^, or TIT* or \Cr, or {Cd. •r = 3.1410, r = radius, C = circumference,... | |
| Wilfred Welday Scott - Metallurgical analysis - 1923 - 918 pages
...multiply the length of one side by the vertical distance to the parallel side. Trapezoid. Area = multiply half the sum of the parallel sides by the perpendicular distance between the two. Circle. Area = 0.7Sa4<P, or irr" or \Cr, or }C<i. r = 3.1416, r = radius, C = circumference,... | |
| Edwin Lovejoy Currier, Nels Johann Lennes, Archibald Shepard Merrill - Agriculture - 1924 - 312 pages
...The area of a four-sided figure two of whose sides are parallel (a trapezoid) is found by multiplying half the sum of the parallel sides by the perpendicular distance between them. In some cases the field may be divided into triangles whose area may be found by taking one half the... | |
| Anthony Nesbit - Measurement - 1859 - 482 pages
...is its area ? Ans. 1131ft. 2 in. 9 pa. PROBLEM VDI. To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
| Steam engineering - 1905 - 572 pages
...area of a trapesoid, or a quadrangle, two of ivhose opposite sides are parallel. Rule — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. DC A E, Fig. 8. Ex. i — What is the area of a trapezoid, Fig.... | |
| |