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" If two triangles have two sides and the included angle of the one, equal to two sides and the included angle of the other, each to each, the two triangles will be equal in all their parts." Axiom 1. "Things which are equal to the same thing, are equal... "
A Treatise on Special Or Elementary Geometry - Page 137
by Edward Olney - 1872 - 239 pages
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Elements of Plane and Solid Geometry

George Albert Wentworth - Geometry - 1877 - 436 pages
...straight line so as to make the adj. A equal, each ¿is a rt. Z ). QED PROPOSITION XLIV. THEOREM. 140. Two parallelograms, having two sides and the included angle of the one equal respectively to two sides and the included angle of the other, are equal in all respects. B С B' С'...
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Elements of Plane Geometry, Part 1

Thomas Hunter - Geometry, Plane - 1878 - 142 pages
...be equal. the angles CBE and FAD are equal (Prop. XXXIII., Bk. I.). Hence these triangles have two sides and the included angle of the one equal to two...and the included angle of the -other, each to each; they are, thereF ED CJPJ! C AB A. B fore, equal in all their parts. If, now, from the whole figure...
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Elements of Geometry: And the First Principles of Modern Geometry

William Henry Harrison Phillips - Geometry - 1878 - 236 pages
...34). xxii. If two spherical triangles on the same sphere, or equal spheres, have tivo sides and th& included angle of the one equal to two sides and- the included angle of the other, each to each, the two triangles will be congruent or symmetrical, and hence equal (15). xxui. If two spherical triangles...
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The Elements of Plane and Solid Geometry: With Chapters on Mensuration and ...

Isaac Sharpless - Geometry - 1879 - 282 pages
...required triangle. Proposition 7. Theorem.—If two triangles have two sides and the included angle of one, equal to two sides and the included angle of the other, each to each, the triangles will be equal in all their parts. Let ABC, DEF be two triangles which have BA, AC, and...
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An Elementary Geometry: Plane, Solid and Spherical

William Frothingham Bradbury - Geometry - 1880 - 260 pages
...and the angle DBC—CDB; therefore the whole angle ABC = ADC; therefore the triangles ABC and ADC, having two sides and the included angle of the one equal to two sides and the included angle of the other, are equal (80). 89. Scholium. In equal triangles the equal angles are opposite the equal...
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Elements of Geometry, Conic Sections, and Plane Trigonometry

Elias Loomis - Conic sections - 1880 - 452 pages
...and B are mutually equilateral. PROPOSITION XII. THEOREM. If two triangles on equal spheres have two sides and the included angle of the one equal to two sides and the included anrjle of the other each to each, their third sides will be equal, and their other angles will be equal...
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First principles of Euclid: an introduction to the study of the first book ...

T S. Taylor - 1880 - 152 pages
...lines to cut off a part equal to the less. 3. If two triangles have two sides and the included angle of one, equal to two sides and the included angle of the other each to each, the bases shall be equal. NOTE. — When two sides of a triangle have been mentioned, the third side...
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Elements of Geometry

George Albert Wentworth - 1881 - 266 pages
...straight line so as to make the adj. /a equal, each Лis a rt. Z ). QED PROPOSITION XLIV. THEOREM. 140. Two parallelograms, having two sides and the included angle of the one equal respectively to two sides and the included angle of the other, are equal in all respects. B CD О A...
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Elements of Geometry

Simon Newcomb - Geometry - 1881 - 418 pages
...= right angle DBC+ angle ABC. Angle FBC = right angle FBA + angle ABC. Therefore the two triangles having two sides and the included angle of the one equal to tAvo sides and the included angle of the other are identically equal, so that Area ABD = area FBC....
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A Treatise on Special Or Elementary Geometry

Edward Olney - Geometry - 1882 - 262 pages
...case— except the fifth— that the truth applies to any other form of quadrilateral.] PROPOSITION XV. \ 301. Theorem. — Two parallelograms having two sides...AD = EH, AB = EF, and A = E ; then are they equal. 7/C For, applying the angle E to A, since EH / — AD, H will fall at D ; and since EF = AB, . k F...
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