| Edward Brooks - Geometry, Modern - 1901 - 278 pages
...for its equal BD, We have AD + DO BC, or AC> BC. Therefore, etc. PROPOSITION XXV. — THEOREM. // two **triangles have two sides of the one respectively equal to two sides of the other,** and the included angles unequal, the third side will be greater in the triangle having the greater... | |
| Edinburgh Mathematical Society - Electronic journals - 1901 - 232 pages
...and EC. Then we can show that AD" and AD' are each less than BE. First, the triangles AD'B and BEA **have two sides of the one respectively equal to two sides of the other,** but the included angles A and B unequal (since BC> AC). As the angle A > the angle B, we find BE>AD'.... | |
| William Chauvenet - 1905 - 336 pages
...the triangle which has the greater included angle has the greater third side. PROPOSITION XV. If two **triangles have two sides of the one respectively equal to two sides of the other,** and the third sides unequal, the triangle which has the greater third side has the greater included... | |
| Elmer Adelbert Lyman - Geometry - 1908 - 364 pages
...BC? within the A ABC? Draw figures for these two cases and apply the proof. THEOREM XI 132. If two **triangles have two sides of the one respectively equal to two sides of the other,** and the third sides unequal, the triangle which has the greater third side has the greater included... | |
| Newfoundland Council of Higher Education - 1911 - 250 pages
...be bisected by lines which meet at 0, show that A OB is also an isosceles triangle. (10) A 3. If two **triangles have two sides of the one respectively equal to two sides of the other,** and have likewise their bases equal, show that the angle which is contained by the two sides of the... | |
| Edith Long, William Charles Brenke - Geometry, Modern - 1916 - 292 pages
...of the third side. Problem XII. To divide a line-segment into n equal parts. Theorem XXXIII. If two **triangles have two sides of the one respectively equal to two sides of the other,** but the included angles unequal, then the third sides are unequal, the greater side being opposite... | |
| Jacob William Albert Young, Lambert Lincoln Jackson - Geometry, Plane - 1916 - 328 pages
...telephone is located at C, \ mi. east of _ Washington [ Square -E. PROPOSITION XV. THEOREM 121. If two **triangles have two sides of the one respectively equal to two sides of the other,** but the included angle of the first greater than the included angle of the second, then the third side... | |
| Edith Long, William Charles Brenke - Geometry, Modern - 1916 - 292 pages
...the third sides are unequal, the greater side being opposite the greater angle. Theorem XXXIV. If two **triangles have two sides of the one respectively equal to two sides of the other,** but the third sides unequal, then the included angles are unequal, the greater angle being opposite... | |
| Great Britain. Scottish Education Dept - 1896 - 642 pages
...different steps neatly arranged. Attention to these points will secure additional marks. 1. If two **triangles have two sides of the one respectively equal to two sides of the other,** and have also the angles equal which are opposite to the greater of the given sides, the triangles... | |
| Edinburgh Mathematical Society - Electronic journals - 1900 - 410 pages
...and EC. Then we can show that AD" and AD' are each less than BE. First, the triangles AD'B and BEA **have two sides of the one respectively equal to two sides of the other,** but the included angles A and В unequal (since BC> AC). As the angle A > the angle B, wefindBE>AD'.... | |
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