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" If two triangles have two sides of the one respectively equal to two sides of the other, and the contained angles supplemental, the two triangles are equal. "
Gradations in Euclid : books i. and ii., with an explanatory preface [&c ... - Page 93
by Euclides - 1858
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Plane Geometry: A Complete Course in the Elements of the Science

Edward Brooks - Geometry, Modern - 1901 - 278 pages
...for its equal BD, We have AD + DO BC, or AC> BC. Therefore, etc. PROPOSITION XXV. — THEOREM. // two triangles have two sides of the one respectively equal to two sides of the other, and the included angles unequal, the third side will be greater in the triangle having the greater...
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Proceedings of the Edinburgh Mathematical Society, Volumes 19-20

Edinburgh Mathematical Society - Electronic journals - 1901 - 232 pages
...and EC. Then we can show that AD" and AD' are each less than BE. First, the triangles AD'B and BEA have two sides of the one respectively equal to two sides of the other, but the included angles A and B unequal (since BC> AC). As the angle A > the angle B, we find BE>AD'....
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Treatise on Elementary Geometry

William Chauvenet - 1905 - 336 pages
...the triangle which has the greater included angle has the greater third side. PROPOSITION XV. If two triangles have two sides of the one respectively equal to two sides of the other, and the third sides unequal, the triangle which has the greater third side has the greater included...
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Plane and Solid Geometry

Elmer Adelbert Lyman - Geometry - 1908 - 364 pages
...BC? within the A ABC? Draw figures for these two cases and apply the proof. THEOREM XI 132. If two triangles have two sides of the one respectively equal to two sides of the other, and the third sides unequal, the triangle which has the greater third side has the greater included...
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Report of the Examinations Conducted by the Council of Higher Education ...

Newfoundland Council of Higher Education - 1911 - 250 pages
...be bisected by lines which meet at 0, show that A OB is also an isosceles triangle. (10) A 3. If two triangles have two sides of the one respectively equal to two sides of the other, and have likewise their bases equal, show that the angle which is contained by the two sides of the...
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Plane Geometry

Edith Long, William Charles Brenke - Geometry, Modern - 1916 - 292 pages
...of the third side. Problem XII. To divide a line-segment into n equal parts. Theorem XXXIII. If two triangles have two sides of the one respectively equal to two sides of the other, but the included angles unequal, then the third sides are unequal, the greater side being opposite...
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Plane Geometry

Jacob William Albert Young, Lambert Lincoln Jackson - Geometry, Plane - 1916 - 328 pages
...telephone is located at C, \ mi. east of _ Washington [ Square -E. PROPOSITION XV. THEOREM 121. If two triangles have two sides of the one respectively equal to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side...
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Plane Geometry

Edith Long, William Charles Brenke - Geometry, Modern - 1916 - 292 pages
...the third sides are unequal, the greater side being opposite the greater angle. Theorem XXXIV. If two triangles have two sides of the one respectively equal to two sides of the other, but the third sides unequal, then the included angles are unequal, the greater angle being opposite...
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Education in Scotland

Great Britain. Scottish Education Dept - 1896 - 642 pages
...different steps neatly arranged. Attention to these points will secure additional marks. 1. If two triangles have two sides of the one respectively equal to two sides of the other, and have also the angles equal which are opposite to the greater of the given sides, the triangles...
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Proceedings of the Edinburgh Mathematical Society, Volumes 18-20

Edinburgh Mathematical Society - Electronic journals - 1900 - 410 pages
...and EC. Then we can show that AD" and AD' are each less than BE. First, the triangles AD'B and BEA have two sides of the one respectively equal to two sides of the other, but the included angles A and В unequal (since BC> AC). As the angle A > the angle B, wefindBE>AD'....
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