...proportional between the hypotenuse and the perpendicular upon it from the vertex of the right angle. 450. The area of a triangle is equal to half the product of its perim451. The perimeter of a triangle is to one side as the perpendicular from the opposite vertex...

...The area of a parallelogram is equal to the product of its base and its altitude. 248. Theorem. The area of a triangle is equal to half the product of its base and its altitude. 249. Corollary. Triangles having equal bases and equal altitudes are equivalent....

...parallelograms hav- « «""/ ~ " , ing the same base and altitude. 3. Show from the facts learned that the area of a triangle is equal to half the product of its base by its altitude ; ie, -, 2 2 4. Draw a right triangle whose base is 3 in. and whose perpendicular...

...from the vertex of the angle opposite the base to the base, or to the base produced ; as B D. 462. The area of a triangle is equal to half the product of its base and altitude. NOTE. For demonstration of the principles of Mensuration, Geometry must be consulted....

...parallelograms hav- « «"/ Jing the same base and altitude. 3. Show from the facts learned that the area of a triangle is equal to half the product of its base by its altitude ; ie, 4. Draw a right triangle whose base is 3 in. and whose perpendicular is...

...AB = AB : AD. BC: AB = AB : BD. ZB = Z DAB = 45°. « 334) (g 156) BC : AB = AB : AD. Ex. 450. The area of a triangle is equal to half the product of its perimeter by the radius of the inscribed circle. 150 151 To prove . area & = \(AB + BC -r CA) x OK PROOF. The...

...are supplements of each other. 6. Construct a square, having given its diagonal. 7. Prove that the area of a triangle is equal to half the product of its perimeter by the radius of the inscribed circle. 8. What is the area of the ring between two concentric circumferences...

...are supplements of each other. 6. Construct a square, having given its diagonal. 7. Prove that the area of a triangle is equal to half the product of its perimeter by the radius of the inscribed circle. Sheffield Scientific School, June, 1892. [NOTE.—State at the...

...are supplements of each other. 6. Construct a square, having given its diagonal. 7. Prove that the area of a triangle is equal to half the product of its perimeter by the radius of the inscribed circle. Sheffield Scientific School, June, 18%. [NOTE. — State at...

...triangle in a given square, so as to have a vertex of the triangle at a vertex of the square. 33. The area of a triangle is equal to half the product of its perimeter by the radius of the inscribed circle. 84. The Egyptians said : " Construct a square the side of which...