 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry, Plane - 1915 - 296 pages
...parallelogram construct a rhombus equal in area to the parallelogram. THE TRIANGLE 362. Theorem. The area of a triangle is equal to half the product of its base and its altitude. A = \bh. Given AACE with base b and altitude h. To prove area of AACE = ^bh.... | |
 | John Charles Stone, James Franklin Millis - Geometry - 1916 - 298 pages
...formed by the line-segments joining the middle points. 38. The area of a triangle equals one half of the product of its perimeter and the radius of the inscribed circle. 39. The papyrus of Ahmes, the oldest mathematical book extant, written by the Egyptian about 1700 BC,... | |
 | William Betz - Geometry - 1916 - 536 pages
...out edge to edge on a street 100 ft. wide, how many miles of the street would be covered? 333. The area of a triangle is equal to half the product of its base and altitude. Or -xC Given the triangle ABC, with the base 6 and the altitude h. To prove that... | |
 | William Betz, Harrison Emmett Webb - Geometry, Solid - 1916 - 214 pages
...altitude. 329. Two parallelograms are to each other as the products of their bases and altitudes. 333. The area of a triangle is equal to half the product of its base and altitude. 334. If T and T' are the areas of two triangles with bases b and b'j and altitudes... | |
 | John H. Williams, Kenneth P. Williams - Geometry, Solid - 1916 - 184 pages
...by its altitude. 347. Parallelograms having equal bases and equal altitudes are equivalent. 349. The area of a triangle is equal to half the product of its base by its altitude. 352. The area of a trapezoid is equal to half the product of its altitude by... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Geometry, Solid - 1917 - 220 pages
...altitude. 339. The area of a parallelogram is equal to the product of its base and its altitude. 343. The area of a triangle is equal to half the product of its base and its altitude. 344. Triangles which have equal bases and equal altitudes (or which have equal... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Geometry, Plane - 1917 - 330 pages
...parallelogram is 255.78 sq. ft. and the base is 12.6 ft. Find the altitude. PROPOSITION V. THEOREM 343. The area of a triangle is equal to half the product of its base and its altitude. D 7 Given the A ABC with the base AC (denoted by 6), and the altitude FB (denoted... | |
 | Mathematics - 1917 - 284 pages
...Substituting for area of FMLP its equal, area of PARL we have : Area of PARL = PL X ML. QED 133a. Theorem: The area of a triangle is equal to half the product of its base by its altitude. Given: CD the altitude of A ABC, AB the base. To prove: Area of A ACS = 1/2 AB... | |
 | Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry - 1918 - 460 pages
...of its sides equal to a given straight line. Is it always possible? THE TRIANGLE 362. Theorem. The area of a triangle is equal to half the product of its base and its altitude. A = Given AACE with base b and altitude h. To prove area of AACE = %bh. Proof.... | |
 | George Wentworth, David Eugene Smith, Joseph Clifton Brown - Mathematics - 1918 - 300 pages
...quantities equal to the same quantity are equal to each other ? THEOREM. AREA OF A TRIANGLE 128. The area of a triangle is equal to half the product of its base and its height. E D a Given the triangle ABC, with base BC and height AD. To prove that the area... | |
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The area of a triangle is equal to half the product of its base by its altitude. 
