 | Euclides - 1852 - 152 pages
...1. All the interior angles of any rectilinear figure, BOOK I. together with four right angles, are equal to twice as many right angles as the figure has sides. For any rectilinear figure ABODE can be divided into as many triangles as the figure has sides, by... | |
 | Euclid - Geometry - 1853 - 176 pages
...rectilinear. Idem • . CONSEQUENCES. The sum of all the internal {angles, together with four right angles, is equal to twice as many right angles as the figure has sides. {All its external angles are together equal to four right angles. L. Relative to Circles generally.... | |
 | Euclides - 1853 - 146 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. COK. 2. — All the exterior angles of any rectilineal figure are together equal to four right angles.... | |
 | Euclides - 1853 - 176 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Сод. 2. All the exterior angles of any rectilineal figure are together equal to four right ,ingles.... | |
 | Royal Military Academy, Woolwich - Mathematics - 1853 - 400 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. COR. 2. All the exterior angles of any rectilineal figure are together equal to four right angles.... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...is equal to the angle B, and the other part DAE is equal to the angle C. PROPOSITION XXVI. THEOREM. The sum of all the interior angles of a polygon, is equal to twice as many right angles, less four, as the figure has sides. Let ABCDE be any polygon : then will the sum of its interior angles... | |
 | E. W. Beans - Surveying - 1854 - 114 pages
...taken. If the entire survey has been made as above directed, the sum of all the internal angles will be equal to twice as many right angles as the figure has sides, diminished by four right angles. If this sum, as in practice will be likely to be the case, should... | |
 | Thomas Holloway (surveyor.) - 1881 - 132 pages
...degrees. 3. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Although further systems of proof could easily be quoted, I consider the foregoing quite sufficient... | |
 | John Gibson - 1881 - 302 pages
...opposite to it. 3. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 4. Describe a parallelogram that shall be equal to a given triangle BCD, and have one of its angles... | |
 | Thomas Newton Andrews - Geometry - 1881 - 168 pages
...proved that "All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides." If we have to describe a pentagon on the base AB, we must first calculate the angles at the base. Thus... | |
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