 | John Playfair - Geometry - 1836 - 148 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. COR. II. All the exterior angles of any rectilineal figure are together equal to four right angles.... | |
 | Mathematics - 1836 - 488 pages
...triangle are equal to two right angles. Сон. 1. All the interior angles of any rectilineal figure are equal to twice as many right angles as the figure has sides, wanting four right angles» 2. All the exterior angles of any rectilineal figure are to. gether equal... | |
 | Charles Reiner - Geometry - 1837 - 254 pages
...the common vertex of these triangles = 4 rt. /.s; therefore, the sum 01 the interior angles of any polygon is equal to twice as many right angles as the figure has sides less [minus] four. M.—If the number of sides be three, four, five, six, seven, &c., what is the sum... | |
 | Benjamin Peirce - Geometry - 1837 - 216 pages
...exterior angle BCD is equal to the sum of the two opposite interior angles A and C. :':71. Theorem. The sum of all the interior angles of a polygon is equal to as many times two right angles as it has sides minus two. • . Demonstration. Let ABODE, &-c. (fig.... | |
 | Adrien Marie Legendre - Geometry - 1837 - 376 pages
...equal to two right angles, taken as many times, less two, as the polygon has sides (Prop. XXVI.) ; that is, equal to twice as many right angles as the figure has sides, wanting four right angles. Hence, the interior angles plus four right angles, is equal to twice as... | |
 | Charles Reiner - Geometry - 1837 - 246 pages
...resolved into as many triangles as the figure has sides ; the sum total of their angles is, therefore, equal to twice as many right angles as the figure has sides. Now, the sum of the angles about the common vertex of these triangles = 4 rt. /.s; therefore, the sum... | |
 | Euclid, James Thomson - Geometry - 1837 - 410 pages
...&c. Cor. 1. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides, by... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...you go along, as also the angles. angles, A, B, C, &c. of the figure together, and their sum must be equal to twice as many right angles as the figure has sides, wanting four right angles. But when the figure has a re-enterant angle, as F, measure the external... | |
 | Andrew Bell - Euclid's Elements - 1837 - 290 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Let the sum of the interior angles be denoted by I, the number of sides by n, and a right angle by... | |
 | Adrien Marie Legendre - Geometry - 1838 - 382 pages
...equal to the angle B, and the other part DAE is equal to the angle C. PROPOSITION XXVI. THEOREM. Tile sum of all the interior angles of a polygon, is equal to two right angles, taken as many times less two, as the figure has sides. Let ABCDEFG be the proposed... | |
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All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
